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LuckyWell [14K]
3 years ago
15

Troy, Xavier, and Emmitt are all football players. They decide to race each other up the bleachers one day. They take off runnin

g and Troy makes it to the top of the bleachers in 10 seconds, beating Emmitt by three seconds and beating Xaiver by five seconds. The bleachers are approximately 50 meters tall. Troy weighs approximately 1200 N, Emmitt weighs approximately 1750 N, and Xaiver is approximately 2100 N.
Physics
1 answer:
zvonat [6]3 years ago
4 0
Is this the answer for the question or is there a question for us?
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Why are road accidents at high speeds very much worse than road accidents at low speeds?
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Answer:

The momentum makes it worse.

Explanation:

The momentum of vehicles running at faster speeds is very high and causes a lot of damage to the vehicles.

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What are the symptoms of hepatitis 'b'​
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7 0
3 years ago
A car starts at zero and gets to 50 km/hour in 10 minutes. What is the initial velocity?
gladu [14]
The initial velocity is the speed and direction of the car at the beginning
of the event. 

You just said that the car "starts at zero".  You might mean that it starts at
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so it sounds like the "zero" at which it starts is zero speed.

In that case, its initial velocity is zero.

6 0
3 years ago
A block of mass m = 2.5 kg is attached to a spring with spring constant k = 730 N/m. It is initially at rest on an inclined plan
Alona [7]

Answer:

A) Em = 4.41 J

B) L = 0.33m

Explanation:

A) The total mechanical energy of the block is the elastic potential energy due to the compressed spring. The gravitational energy is zero. Then you have:

E_m=\frac{1}{2}k(\Delta x)^2

k: constant's spring = 730 N/m

Δx: distance of the compression = 0.11m

You replace the values of k and Δx:

E_m=\frac{1}{2}(730N/m)(0.11m)^2=4.41\ J

B) To find the distance L traveled by the block you take into account that the total mechanical energy of the block is countered by the work done by the friction force, and also by the work done by the gravitational energy.

Then, you have:

E_m-W_f-W_g=0\\\\W_f=(\mu Mg cos\theta)L\\\\W_g=(Mgsin\theta)L

μ:  coefficient of kinetic friction = 0.19

g: gravitational acceleration = 9.8m/s^2

M: mass of the block = 2.5kg

θ: angle of the inclined plane = 21°

You replace the values of all parameters:

E_m-W_f-W_g=0\\\\4.41-(0.19)(2.5kg)(9.8m/s^2)(cos21\°)L-(2.5kg)(9.8m/s^2)(sin21\°)L=0\\\\4.41-4.34L-8.78L=0\\\\4.41-13.12L=0\\\\L=0.33m

hence, the distance L in which the block stops is 0.33m

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3 years ago
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creativ13 [48]

' C ' is the only correct statement on the list.  We don't know anything about diagram-x or diagram-y because we can't see them.

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