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Cloud [144]
3 years ago
9

An ant moves towards the plane mirror with speed of 2 m/s & the mirror is moved towards the ant with the same speed. What is

the relative velocity between the ant and its image?​
Physics
1 answer:
Stells [14]3 years ago
6 0
  • Speed of ant-V_a=2m/s
  • Speed of mirror =v_b=2m/s

We know

\boxed{\sf Relative\:velocity(V_{AB})=V_A-V_B}

\\ \sf\longmapsto V_{AB}=2-2

\\ \sf\longmapsto V_{AB}=0m/s

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a meteoroid changed velocity from 1.0km/s to 1.8 km/s in 0.03 seconds. what is the acceleration of the meteoroid
Greeley [361]
A meteoroid changed velocity from 1.0 km/s to 1.8 km/s in 0.03 seconds.
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3 years ago
Why when i take "The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it c
timurjin [86]

Answer:

NOOOOOOO NOT THE PACER TEST!!

Explanation:

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6 0
3 years ago
how much force ks required.to.keep 780 n box moving at constant velocityu across.the floor if friction force betwern the bix and
icang [17]

Answer:

Explanation:you must first make a free body diagram of the block to place all the forces that act on the block there. You will have four forces. The normal force, the weight, the horizontal force in x (which is what they ask to calculate) and the friction force. Then you raise the equations and you clear the values. I attach the solution.

8 0
3 years ago
An organ pipe of length 50 cm, open at one end, has a fundamental frequency of 171 Hz. Calculate the speed of sound in the pipe.
antiseptic1488 [7]

Answer:

wavelength = 2m

Speed = 342m/s

Explanation:

The length of the pipe in terms of the wavelength is expressed as;

L = v/4 (For closed pipe)

v = 4L

Given

L = 50cm

L = 0.5m

Get the wavelength v;

v = 4(0.5)

v = 2.0m

Hence the wavelength is 2.0m

The speed of the sound in pipe is expressed as;

Fo = V/4L

Fo is the fundamental frequency

V is the speed of sound

L is the length of the pipe

171 = V/4(0.5)

V = 171 * 2

V = 342m/s

Hence the speed of the sound in pipe is 342m/s

3 0
3 years ago
A 55-liter tank is full and contains 40kg of fuel. Find using Sl units: • Density p. • Specific Weight y • Specific Gravity Answ
Pavlova-9 [17]

Answer:

p = 727.273 kg/m3,  y = 7134.545 N/m^3, SG = 0.7273

Explanation:

Density is simply the amount of mass of a substance per unit of volume. It can be found by dividing the mass in kg by the volume im m^3:

p = \frac{m}{v}  = \frac{40kg}{55lt*\frac{1 m^3}{1000 lt}} = 727.273 kg/m^3

Specific weight is the weight of the substance per unit of volume. The weight is the mass of the material times the gravity, and it represents the force that the earth exerts on an object. Another way of calculate this value, its multiplying the density of the fuel times the gravity. Then:

y =  p*g = 727.273 kg/m^3 * 9.81 m/s^2 = 7134.545 N/m^3

Specific Gravity is the ratio of the density of the substance to the density of a reference substance. For liquids, the reference substance is water at 4°C, which has a density of about 1000 kg/m^3.

SG =\frac{ p_{fuel}}{p_{water}}  = \frac{727.273 kg/m^3}{1000 kg/m^3} = 0.7273

3 0
3 years ago
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