The time difference between their landing is 2.04 seconds.
<h3>
Time of difference of the two balls</h3>
The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.
Time difference, = 2t - t = t
t = √(2h/g)
where;
- h is the height of fall
- g is acceleration due to gravity
Apply the principle of conservation of energy;
¹/₂mv² = mgh
h = v²/2g
where;
h = (20²)/(2 x 9.8)
h = 20.41 m
<h3>Time of motion</h3>
t = √(2 x 20.41 / 9.8)
t = 2.04 s
Thus, the time difference between their landing is 2.04 seconds.
Learn more about time of motion here: brainly.com/question/2364404
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Answer:
4Q
Explanation:
Case 1 :
= mass of the metal
= specific heat of the metal
= Change in temperature = 7 - 4 = 3 C
Amount of heat required for the above change of temperature is given as

Case 2 :
= mass of the metal
= specific heat of the metal
= Change in temperature = 19 - 7 = 12 C
Amount of heat required for the above change of temperature is given as

Hence the correct choice is
4Q
Answer:
Whether the force exerted by the locomotive on the wall was larger
Than the force the locomotive could exert on the wall.
Explanation:
The Newton's third law of motion States that every force have it's equal and opposite reaction force, whose magnitude is the same as the applied force. Therefore the magnitude of these opposite forces will be equal.
So we have;
F12=-F21
F12 is the force in a direction
-F21 is the force in the opposite direction.
Therefore we see that the magnitude of the force the locomotive exerts on the wall is equal to the one the wall exerts on the locomotive. Both magnitudes are equal but in opposite directions.
Answer:
a)
b)
c)
The estimate is low.
Explanation:
a) Using the energy conservation we have:

we have kinetic energy intially and gravitational potential energy at the maximum height.


b) We can use the equation of the gravitational force
(1)
We have that:
(2)
at the surface G will be:

Now the equation of an object at a distance x from the surface.
is:


Using that dv/dt is vdx/dt and integrating in both sides we have:



c) The difference is:
So the percent difference will be:


The estimate is low.
I hope it helps you!