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Oduvanchick [21]
3 years ago
7

A fan at a rock concert is 50.0 m from the stage, and at this point the sound intensity level is 108dB. Sound is detected when a

sound wave causes the tympanic membrane (the eardrum) to vibrate. Typically, the diameter of this membrane is about 8.40 mm in humans. Answer the following:
How much energy is transferred to her eardrums each second ?
How fast would a 2.00 mg mosquito have to fly to have this much kinetic energy?
How fast a typical 2.0 mg mosquito would have to fly (in mm/s) to have an amount of energy delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?
Physics
1 answer:
Andre45 [30]3 years ago
4 0
Based on your question the answer to this is the following and i hope i answered you question correctly:

How much energy is transferred to her eardrums each second ? 
-6.31
<span>
How fast would a 2.00 mg mosquito have to fly to have this much kinetic energy? </span>
-1.39*10^-5<span>

How fast a typical 2.0 mg mosquito would have to fly (in mm/s) to have an amount of energy delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?
-</span><span>3.5 joules</span>

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Throw two balls from the same height at the same time at an initial speed of 20 m/s. One is thrown vertically down, while the ot
labwork [276]

The time difference between their landing is 2.04 seconds.

<h3>Time of difference of the two balls</h3>

The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.

Time difference, = 2t - t = t

t = √(2h/g)

where;

  • h is the height of fall
  • g is acceleration due to gravity

Apply the principle of conservation of energy;

¹/₂mv² = mgh

h = v²/2g

where;

  • v is speed of the ball

h = (20²)/(2 x 9.8)

h = 20.41 m

<h3>Time of motion</h3>

t = √(2 x 20.41 / 9.8)

t = 2.04 s

Thus, the time difference between their landing is 2.04 seconds.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

6 0
2 years ago
If heat Q is required to increase the temperature of a metal object from 4 ∘C to 7∘C, the amount of heat necessary to increase i
alisha [4.7K]

Answer:

4Q

Explanation:

Case 1 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 7 - 4 = 3 C

Amount of heat required for the above change of temperature is given as

Q = m c \Delta T\\Q = m c (7 - 4)\\Q = 3 m c

Case 2 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 19 - 7 = 12 C

Amount of heat required for the above change of temperature is given as

Q' = m c \Delta T\\Q' = m c (12)\\Q' = (4)(3 m c)\\Q' = 4Q

Hence the correct choice is

4Q

6 0
3 years ago
Read 2 more answers
In the photo, a locomotive has broken through the wall of a train station. During the collision, what can be said about the forc
Pavlova-9 [17]

Answer:

Whether the force exerted by the locomotive on the wall was larger

Than the force the locomotive could exert on the wall.

Explanation:

The Newton's third law of motion States that every force have it's equal and opposite reaction force, whose magnitude is the same as the applied force. Therefore the magnitude of these opposite forces will be equal.

So we have;

F12=-F21

F12 is the force in a direction

-F21 is the force in the opposite direction.

Therefore we see that the magnitude of the force the locomotive exerts on the wall is equal to the one the wall exerts on the locomotive. Both magnitudes are equal but in opposite directions.

6 0
4 years ago
In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
Mamont248 [21]

Answer:

a)h_{max}=14536.16 m

b)h = 15687.9 m

c)PD=7.62\% The estimate is low.

Explanation:

a) Using the energy conservation we have:

E_{initial}=E_{final}

we have kinetic energy intially and gravitational potential energy at the maximum height.

\frac{1}{2}mv^{2}=mgh_{max}

h_{max}=\frac{v^{2}}{2g}

h_{max}=\frac{43^{2}}{2*0.0636}

h_{max}=14536.16 m  

b)  We can use the equation of the gravitational force

F=G\frac{mM}{R^{2}}   (1)

We have that:

F = ma    (2)

at the surface G will be:

G=\frac{gR^{2}}{M}

Now the equation of an object at a distance x from the surface.

is:

F=\frac{mgR^{2}}{(R+x)^{2}}

m\frac{dv}{dt}=\frac{mgR^{2}}{(R+x)^{2}}

Using that dv/dt is vdx/dt and integrating in both sides we have:

v_{0}=\sqrt{\frac{2gRh}{R+h}}

h=\frac{v_{0}^{2}R}{2gR-v_{0}^{2}}

h=15687.9

c) The difference is:

So the percent difference will be:

PD=|\frac{14536.16-15687.9}{(14536.16+15687.9)/2}*100%

PD=7.62\%

The estimate is low.

I hope it helps you!

7 0
3 years ago
An empty corn silo in the shape of a cylinder is being filled with corn
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Answer: 8250

Explanation:

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