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allsm [11]
2 years ago
6

To make it more easier for everyone, it's on Khan Academy and this problem is in Algebra 1 to be specific. Solve for x.

Mathematics
1 answer:
jolli1 [7]2 years ago
3 0

Answer:

B: x≤5

Step-by-step explanation:

Hi there!

We're given two inequalities; 3x−8≤23  and −4x+26≥6

We need to find the values of x that make BOTH of the inequalities true (which is the intersection of the two inequality graphs)

First, let's solve for x in both of them

taking the first inequality:

3x−8≤23  

add 8 to both sides

3x≤31

divide by 3

x≤31/3

now solve for x in −4x+26≥6

subtract 26 from both sides

-4x≥-20

divide both sides by -4 and remember to FLIP the inequality sign since we have a negative number

x≤5

now let's graph these two inequalities to find the intersection, and that is below with the answer

Hope this helps! :)

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Answer:

  y +8 = -4(x -8)

Step-by-step explanation:

You recognize that the given equation is in slope-intercept form:

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A perpendicular line will have a slope that is the negative reciprocal of this value of m, so the desired slope is ...

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The point-slope form of the equation for a line is ...

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Using m=-4 and (h, k) = (8, -8), the point-slope form of the equation for the line you want is ...

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