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shepuryov [24]
3 years ago
7

HELP ME POR FAVOR PLEASE PLEASEE

Mathematics
1 answer:
Basile [38]3 years ago
3 0

Answer:

                 x=8\frac34\ \,,\quad y=8\frac12

Step-by-step explanation:

             \Delta TRS\sim \Delta LJK \quad\implies\quad \dfrac{|TR|}{|LJ|}=\dfrac{|RS|}{|JK|}=\dfrac{|ST|}{|KL|}\\\\\dfrac{4}{7}=\dfrac{5}{x}=\dfrac{6}{y+2}\\\\\\\dfrac{4}{7}=\dfrac{5}{x}\quad\implies\quad4x=5\cdot7\quad\implies\quad x=\dfrac{35}4=8\frac34\\\\\\\dfrac{5}{x}=\dfrac{6}{y+2}\quad\implies\quad 5(y+2)=6\cdot\dfrac{35}4\\\\5y+10=3\cdot\dfrac{35}2\\\\5y\ =\ \dfrac{3\cdot35}2-10\\ \div5\qquad\quad \div5\\\\y=\dfrac{3\cdot7}2-2=10\frac12-2=8\frac12

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There are 5 times as many males as females on the maths course at university. What fraction of the course are female?
Valentin [98]

Answer:

1/5 are females i think

Step-by-step explanation:

4 0
3 years ago
This was on my homework 5 X-5 = 5x+7
KengaRu [80]

Answer:

No solution

Step-by-step explanation:

Original Equation:

5x - 5 = 5x + 7

Add 5 to both sides

5x = 5x + 12

So we already know that this equation is not true, making it no solution

Hope this helped

6 0
3 years ago
.46 repeating as a fraction in simplest form
My name is Ann [436]

Answer:

7/15

Step-by-step explanation:

0.4 6  =  0 . 6  - 0.2

0.46  = 6/9 ⋅ 0.9 - 0.2

0.46 = 6/9 - 1/5

0.46 = 2/3 - 1/5

0.46 = 10/15 - 3/15

0.46 = 7/15

Note that  7  and  15  have no common factors larger than  1 , so this is in simplest terms.

4 0
3 years ago
Use the raw data below to create a table that can be used to create a histogram with 5
schepotkina [342]

Answer:

Five classes

Step-by-step explanation:

1. Sort the data

You get

1.1, 1.3, 1.6, 1.7, 2, 2.6, 2.7, 2.9, 3.2, 3.2, 3.5, 3.5, 3.9, 4.6, 4.7, 4.8, 4.8, 4.9, 4.9, 5.3, 5.7, 6.4, 6.5, 7.1, 7.5, 7.6, 8.1, 8.2, 9.2, 9.4

2. Calculate the range

Range = Max - Min = 9.4 - 1.1 = 8.3

3. Calculate the class width

Divide the range by the number of classes

8.3/5 = 1.7

Round this up to 2.

4. Decide where to start the histogram

You could use classes: 1 - 3, 3 - 5, 5 - 7, 7 - 9, 9 -11

However, even numbers are easier to read.

It would be preferable to use classes: 0 - 2, 2 - 4, 4 - 6, 6 - 8, 8 - 10

5. Prepare a frequency distribution table

Note: Each class does not include its largest possible value. Thus, a value of 2 goes into Class 2 - 4, (not Class 0 - 2).

\begin{array}{cc}\textbf{Miles run} & \textbf{No. of students} \\0 - 2 & 4 \\2 - 4 & 9 \\4 - 6 & 8 \\6 - 8 & 5 \\8 - 10 & 4 \\\end{array}

4 0
3 years ago
help, please.. . Let f(x) = 2x2 – 2x + 7 and g(x) = x2 + 9x – 6. Find f(x) – g(x).. . x2 – 11x + 13. . x2 – 11x + 1. . x2 + 7x +
AlladinOne [14]
F(x) = 2x² - 2x + 7

g(x) = x² + 9x - 6

f(x) - g(x) = 2x² - 2x + 7 - (x² + 9x - 6)

                = 2x² - 2x + 7 - x² - 9x + 6

                = 2x² - x² - 2x - 9x + 7 + 6

                = x² - 11x + 13

The 1st option.       
7 0
3 years ago
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