Answer:
Step-by-step explanation:
Set is a well defined collection of objects .
We can express set in roaster form or set - builder form
<u>Roaster Form</u>
We express elements within curly brackets using commas between the elements .
<u>Set Builder Form</u>
In set builder form , all the elements of the set possess a common property which is not possess by elements outside the set .
We describe the elements of set using a symbol x which is followed by a colon . After colon , we write property possessed by the element and then enclosed the description within curly brackets .
(a)The set of all humans whose first name is Tanya or Nelson
We need to write this one in set builder form .
Define set as follows : { x ∈ H : H is set of all the humans and x is either Tanya or Nelson }
Solution
Problem 6
For this case we can do this:
12, 16,__, 14, 8, 7
We can solve for x like this:
Problem 7
F
Answer:
7
Step-by-step explanation:
The first step to solve this problem is to convert 1h 30min into just minutes. since there are 60 minutes in 1 hour you take 60 and add it ot the 30 extra minutes to get a total of 90.
Now, this question is asking you to find how many calories <u>per</u> minute she burns. When you are asked to find ___ per___ all you have to do is divide the first number by the second one. In this case you will divide calories by minutes.
630/90=<u>7</u>
Answer:
2x^2*(2x^3+8x^2+2x) or
4x^5+16x^4+4x^3
Step-by-step explanation:
A=[2x^3-x+(8x^2+3x)]*4x^2/2=2x^2*(2x^3+8x^2+2x)
or A=4x^5+16x^4+4x^3
Hey there! :D
Think of this like a triangle. The dock is 15 feet above ground. It is the side of the triangle. The line connecting the bottom of the dock to the base of the conveyor belt is 40 feet. This is like the base.
The conveyor belt itself is at a diagonal, and should be the hypotenuse.
Use the Pythagorean theorem.
a^2+b^2=c^2
15^2+40^2= c^2
225+1,600= c^2
Add the values together.
1,825= c^2
Find the square root of 1,825.
c= 42.7 (rounded to the nearest tenth)
The conveyor belt is 42.7 feet long.
I hope this helps!
~kaikers
