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4 years ago

How do I solve 6/11 + 1/2 - 1/5

Mathematics

1 answer:

inn [45]4 years ago

4 0

Answer:

0.84545454545

Step-by-step explanation:

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A ball rolls from x = 3.85 m to x = 22.1 m in 5.00 seconds. What was its average velocity?

Paha777 [63]

3.65/per second
Hope it helps

5 0

3 years ago

Read 2 more answers

The resultant of two forces acting at a point at right angles to each other is 32 pounds. If the horizontal force is 19 pounds,

Irina-Kira [14]

Answer:

The vertical force or the other force to the nearest pounds is 26 pounds

Step-by-step explanation:

The resultant force,R = 32 pounds

The horizontal force, (x)= 19 pounds

The vertical force = y

$\theta$ = angle between the vertical and horizontal forces.

$R=\sqrt{x^2+y^2-2xy\cos 90^o}$

$32^2=19^2+y^2-2(19)y\times 0$

$1024-361=y^2$

$y=\sqrt{663}=25.74\approx 26$

The vertical force or the other force to the nearest pounds is 26 pounds

6 0

3 years ago

In a particular region there is a uniform current density of 18 a/m2 in the positive z direction. what is the value of line inte

Ugo [173]

By Stokes' theorem, the integral is 0. If $R$ is the triangular region bounded by the given line segments composing the curve $C$ , then

$\displaystyle\int_{\partial R}\mathbf b\cdot\mathrm d\mathbf s=\iint_R\nabla\times\mathrm d\mathbf r$

where $\nabla\times F=\mathrm{curl}(0,0,18)=0$ .

Just to verify this, we can parameterize the path by

$C=C_1\cup C_2\cup C_3$
$\begin{cases}C_1:=\{(4d,3dt,0)~|~0\le t\le1\}\\C_2:=\{(4d(1-t),3d(1-t),0)~|~0\le t\le1\}\\C_3:=\{(4dt,0,0)~|~0\le t\le1\}\end{cases}$

$\displaystyle\int_C\mathbf b\cdot\mathrm d\mathbf s$
$=\displaystyle\int_0^1(0,0,18)\cdot(0,3d,0)\,\mathrm dt+\int_0^1(0,0,18)\cdot(-4d,-3d,0)\,\mathrm dt+\int_0^1(0,0,18)\cdot(4d,0,0)\,\mathrm dt$
$=0+0+0=0$

7 0

3 years ago

You draw a marble from a bag, and replace it before drawing a second marble from the bag.are the events independent or dependent

omeli [17]

<h3>Answer: Independent </h3>

=======================================================

Reason:

The first marble was replaced, so the original state of the bag hasn't changed overall. The probability isn't changed either. We can treat the second selection entirely independent of the first one.

If the first marble wasn't replaced, then the marble count of course goes down by 1. That affects the probability of the second selection and we'd consider these events to be dependent.

---------

An example:

Consider a bag with 4 red marbles and 6 green ones. The chances of picking red on the first try are 4/10 = 2/5. The chances of picking red again would be 2/5 assuming we put that red marble back. We can see the second selection is independent of the first.

If the marble wasn't put back, then the chances of picking a 2nd red marble would be 3/9 = 1/3. I subtracted 1 from the numerator and denominator of 4/10 to get to 3/9. In this case, the 2nd selection's probability depends on the first event (whether red was picked or not).

4 0

2 years ago

The daily number of miles driven by a bus driver during a week are 50, 65, 78, 54, 53, 61, 79, and 78.

marta [7]

Answer:

C Both the mean and median are appropriate measures of center.

Step-by-step explanation:

5 0

2 years ago