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vampirchik [111]
2 years ago
11

The daily number of miles driven by a bus driver during a week are 50, 65, 78, 54, 53, 61, 79, and 78.

Mathematics
1 answer:
marta [7]2 years ago
5 0

Answer:

C Both the mean and median are appropriate measures of center.

Step-by-step explanation:

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Plz help me plzz i beg of u
Stells [14]

Answer:

2.0 x 10^11

Step-by-step explanation:

2.6 divide it by 1.3 and get 2.0. 9+2 = 11. Together with the, it would be 10^11. That how I got 2.0 x 10^11

Hope this Helps, have a nice day!

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7 0
3 years ago
One bottle contains 250 ml of juice. Soham wants 2 liters of juice. How many bottles should he buy?
Brrunno [24]

Answer:

8 bottles

Step-by-step explanation:

8 0
2 years ago
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Need help! only have today till I turn in!
12345 [234]

Answer:

yes

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7 0
2 years ago
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Owners of 800 homes in a subdivision list their houses, on average, every eight years. If a sales associate farms that neighborh
Gekata [30.6K]

Answer:

20 homes

Step-by-step explanation:

Given that :

Total number of homes = 800

Average years at which homes are listed = 8 years

To obtain the annual home listing = total number of Homes / average years

Annual home listing = 800 / 8

Annual home listing = 100 homes

If 20% of the homes are listed on the year in question :

20% of 100 homes

0.2 * 100

= 20 homes

20 homes can be listed that year

6 0
3 years ago
Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest
Len [333]

The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440  – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

\text {Simple Interest }=\frac{P \times R \times T}{100}

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

1840=\frac{4600 \times R \times 5}{100}

\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}

Hence, the required rate of interest per year is 8%

6 0
3 years ago
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