Answer:
Images are neither similar nor congruent.
Coordinates of (-3,2) when transformed are (-6, 8).
Step-by-step explanation:
In the transformation we are multiplying the coordinates by two different numbers (2 for x, 4 for y ); therefore the transformed figure can neither be similar nor congruent.
This is because a transformation that results in a congruent figure must of of the form 
—this is just shifting the figure.
The transformation that results in a similar figure must be of the form 
or 
—this is just scaling the figure.
Since the transformation 
is neither a congruent transformation nor a similar transformation ,the resulting figure in neither similar nor congruent.
The point (-3, 2) transforms to
Hello,
Answer A (graph most left)
Intersection is (10/3,-11/3)
y=-2x+3
y=-2-x/2
so -2x+3=-2-x/2
==>3x/2=5 ==>x=10/3
and y=-2*10/3+3=-11/3
Answer:
Step-by-step explanation:
Let "a" and "m" represent the cost of an apple and a mango, respectively. Then Cameron's purchase can be represented as ...
4a +7m = 17.75
Gavin's purchase can be represented as ...
2a +5m = 10.75
Subtracting the first equation from twice the second gives ...
2(2a +5m) -(4a +7m) = 2(10.75) -(17.75)
3m = 3.75
m = 1.25
Then the price of an apple can be found from the second equation:
2a +5(1.25) = 10.75
2a = 4.50 . . . . . . . . . . subtract 6.25
a = 2.25 . . . . . . . . . . . divide by 2
The price of an apple was $2.25; the price of a mango was $1.25.
The temperatures (in degrees Fahrenheit) in Long Island recorded by the weather bureau over a week were 42, 49, 53, 55, 50, 47, and 52.
Data arranged in ascending order are : 42, 47, 49,50, 52,53,55
As mean can be find by dividing sum of all the observations divided by total number of observations.
Median gives the middle value of the Data. If number of observation is odd, median =
=
= 4 th observation= 50
If n is even, then Median = Mean of and[ +1 ] th term.
Mode is that data which appears maximum number of times.
Range = Maximum value in a data - Minimum value in the Data
Correct option is Median.
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