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2 years ago

How can you describe the graph of the equation ax + by = c? Explain

Mathematics

1 answer:

natka813 [3]2 years ago

3 0

Answer:

When A and B are not both zero, the graph of Ax + By = C is always a line. The graph of Ax + By = C, where A and B are not both zero, is a line. Divide both sides by B. Because the form Ax + By = C can describe any line, it is called the standard form of an equation for a line.

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What are the coordinates of X?

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Answer:

Step-by-step explanation:

x is at (0, 4)

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2 years ago

Multiplying a vector by a plain number is referred to as scalar multiplication.<br> True or false?

Yuki888 [10]

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Answer:

True

Step-by-step explanation:

In scalar multiplication, each component of the vector is multiplied by the scalar. The description is True.

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2 years ago

Paul purchased 3 video games for $17.25 each. Which expression is the best choice to help him determine the total amount of mone

amid [387]

(3)(17.25) = 51.75; he spent $51.75

Because everything in the problem is positive, no negative numbers are needed.

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3 years ago

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(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

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2 years ago

Joe flips the disc shown below 15 times:

vfiekz [6]

Whatever the number of times you flip the disc, as long as the disc has uniformly distributed mass throughout the body, then

The probability will always be 50%

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2 years ago

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