Question

Pls Helppppp meeeeee!!​

Answer 1

Answer:

G

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals in the expression

$\sqrt{52}$

= $\sqrt{4(13)}$

= $\sqrt{4}$ × $\sqrt{13}$

= 2$\sqrt{13}$

------------------

$\sqrt{117}$

= $\sqrt{9(13)}$

= $\sqrt{9}$ × $\sqrt{13}$

= 3$\sqrt{13}$

Then

$\sqrt{52}$ + $\sqrt{117}$

= 2$\sqrt{13}$ + 3$\sqrt{13}$

= 5$\sqrt{13}$ → G

Answer 2

Problem:-

${\small\sf{The\:expression \sqrt{52} + \sqrt{117} \:is \: equivalent \: to}}$

$\small\bf{F.} \: \sf{13}$

$\small\bf{G.}\sf \:5 \sqrt{13}$

$\small\bf{H.}\sf\:6 \sqrt{13}$

$\small\bf{J.}\sf\:13 \sqrt{13}$

Solution:-

$\small\sqrt{52}+\sqrt{117}\sqrt{4•13} +\sqrt{9•13}\tiny\sf\purple{(Product\:Property)}$

$\small{ \: \:\: \: \: \: \: \:=\sqrt{2²•13}+\sqrt{3²•13}\tiny\sf\purple{(Prime\:Factorization)}}$

$\small{\: \:\: \: \: \: \: \:=\sqrt{2²}\sqrt{13}+\sqrt{3²}\sqrt{13}\tiny\sf\purple{(Product\:Property)}}$

$\small{\: \:\: \: \: \: \: \:=2\sqrt{13}+3\sqrt{13}\tiny\sf\purple{(Simplify)}}$

$\small{\: \:\: \: \: \: \: \:=5\sqrt{13}\tiny\sf\purple{(Simplify)}}$

Answer:-

So, the correct option is D.

=======================

#Hope it helps!

(ノ^_^)ノ