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barxatty [35]
2 years ago
15

GIVING BRAINLIEST PLEASE HELP

Mathematics
1 answer:
Verdich [7]2 years ago
5 0

Answer:

1/3

Step-by-step explanation:

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Please help it's greatly apprecatied
Gala2k [10]

Answer:

Step-by-step explanation: A on edge

3 0
3 years ago
Ryan bought 6 apples and 9 peaches for a total of $7.86. Madi bought 4 apples and 5 peaches for $4.82. How much are apples and p
Scilla [17]
Let, x = The cost of an apple
y = The cost of a peach

6x + 9y = 7.86 - - - - - - - - 1
4x + 5y = 4.82 - - - - - - - - 2

From equation 2,
4x =4.82 - 5y
x= (4.82 - 5y) ÷ 4 - - - - - - - 3

Substitute 3 into 1,
6x + 9y = 7.86
6 [(4.82 - 5y) ÷ 4] + 9y = 7.86
(28.92 - 30 y) ÷4 + 9y = 7.86
28.92 - 30y + 36y = 31.44
6y=2.52
y= 0.42

Substitute y = 0.42 into 2
4x + 5y= 4.82
4x + 5 (0.42) = 4.82
4x + 2.1 = 4.82
4x= 2.72
x= 0.68.

Thus, an apple costs $ 0.68 and a peach costs $ 0.42.

8 0
3 years ago
A coach wants to know if soccer players who warm up before a game will score more points than those who don't warm up. He will b
11Alexandr11 [23.1K]
The correct answer is the last option.

Since the coach is studying the two different groups, the results will be more meaningful if the groups are compared to one another as opposed to the players. It would also make more sense to study the mean (or average) of the points scored, rather than the standard deviation (which is essentially a measure of how spread out a set of numbers are).
6 0
3 years ago
Read 2 more answers
GIVING BRAINLIST IF YOU HELP FAST!
djyliett [7]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER i WILL PUT MOST BRAINLIEST!
galina1969 [7]

Answer:

The correct option is;

c. Because the p-value of 0.1609 is greater than the significance level of 0.05, we fail to reject the null hypothesis. We conclude the data provide convincing evidence that the mean amount of juice in all the bottles filled that day does not differ from the target value of 275 milliliters.

Step-by-step explanation:

Here we have the values

μ = 275 mL

275.4

276.8

273.9

275

275.8

275.9

276.1

Sum = 1928.9

Mean (Average), = 275.5571429

Standard deviation, s = 0.921696159

We put the null hypothesis as H₀: μ₁ = μ₂

Therefore, the alternative becomes Hₐ: μ₁ ≠ μ₂

The t-test formula is as follows;

t=\frac{\bar{x}-\mu }{\frac{s}{\sqrt{n}}}

Plugging in the values, we have,

Test statistic = 1.599292

t_{\alpha /2} at 7 - 1 degrees of freedom and α = 0.05 = ±2.446912

Our p-value from the the test statistic = 0.1608723≈ 0.1609

Therefore since the p-value = 0.1609 > α = 0.05, we fail to reject our null hypothesis, hence the evidence suggests that the mean does not differ from 275 mL.

4 0
3 years ago
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