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Naily [24]
3 years ago
6

To graph the equation 2x + 5y = 10, Zeplyn draws a line through the points (5, 0) and (0, 2). What is the slope of the line repr

esented by 2x + 5y = 10?
negative StartFraction 5 Over 2 EndFraction
negative StartFraction 2 Over 5 EndFraction
StartFraction 2 Over 5 EndFraction
StartFraction 5 Over 2 EndFraction
Mathematics
2 answers:
aliya0001 [1]3 years ago
6 0

Answer:

2/5 (option c)

Step-by-step explanation:

ankoles [38]3 years ago
6 0

Answer:

-2/5

Step-by-step explanation:

The coordinates are (5,0) and (0,2) so you would subtract y2- y1 and x2-x1.

0-5= -5

2-0= 2

y/x also rise/run when looking at a graph

-2/5

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Can someone help me out with these two problems having trouble please !!
eimsori [14]

Answer:

1.

x=-10

x=-6

2.

x=10

x=-3

Step-by-step explanation:

to find the zeros of a function you need to set it equal to zero:

x^2+16x+60=0

then you factor

(x+10)(x+6)=0

then you have to finish factoring/simplifying

x+10=0

  -10

x=-10

x+6=0

 -6

x=-6

and the same thing for number 2

x^2-7x-30=0

(x-10)(x-3)=0

x=10, x=3

3 0
2 years ago
Read 2 more answers
What does a value of 8 in 589310 compare yo the value of the 8 ine 598301​
shepuryov [24]

Answer:

10

Step-by-step explanation:

It is 10 times as much

3 0
2 years ago
please help this is a math question about geometry !!!! please view the attached images to see the question and the answer choic
jolli1 [7]

Answer:

It is the second picture.

Step-by-step explanation:

4 0
2 years ago
What is the least common denominator of the rational expressions below? 1/x^2-5x+3/x^2+2x-35
Komok [63]

Here the denominators are quadratics , so we need to factorise them first

1/(x²-5x) +3/(x²+2x-35)

factorising x²-5x ,

here GCF is x, so taking x out we have

x(x-5)

factorising x²+2x-35 using AC method,

we find factors of -35 that add up to give 2

(x-5)(x+7)

Since we have x-5 common in both denominators, so lcd of the rational expression will be product of x(x-5)(x+7)

lcd is x(x-5)(x+7)

5 0
3 years ago
You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 115 km south and 112 km east. Mt. Rainier is locat
Mars2501 [29]

Answer:

  5 minutes 4.8 seconds

Step-by-step explanation:

We can work this problem several ways. One is to determine the component of the distance from JBLM to the mountain that is in the direction the plane is flying. We can do that by finding the dot product of the vector to the mountain with the normalized direction vector of the airplane:

  JA = JR•(JP/|JP|) . . . . . . where JR = (56, -40) and JP = (112, -115)

  = (56, -40)•(112, -115)/√(112² +115²)

  JA = 10872/√25769 ≈ 67.7268 . . . . km

__

At a speed of 800 km/h, this distance will be covered in ...

  time = distance/speed

  time = (67.7268 km)/(800 km/h) = 0.0846585 h

That's about 5 minutes, 4.8 seconds.

_____

In the attached diagram, J represents JBLM, R represents Mt. Rainier, A represents the point of closest approach, and P would represent the location of the airplane after 1 hour of flying time, (112, -115). In the above, we have used the names of these line segments/vectors.

6 0
3 years ago
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