Answer:
Step-by-step explanation:
A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?
This is a circle inscribed in an equilateral triangle with side s.
If you are asking for the perimeter of PQR, it is 3s.
If you are asking for the perimeter of OQR, it is (3+23–√3)s
Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.
(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s
Hope it helps
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Answer:
See Explanation
Step-by-step explanation:
According to the Question,
Steps of construction:
- Step I - Draw a line segment AB = 7 cm with the help ruler.
- Step II - with vertex A, by using compass take more than half of AB and draw arcs, one on each side of AB.
- Step III - with vertex B, by using a compass with the same length, cut the previous arcs at X and Y respectively.
- Step IV - with help of the ruler join the points X and Y Thus XY is the perpendicular bisector of line AB.
(For Diagram please find in attachment)
Perimeter divided by base??
Answer:
If the committee must consist at least one student, the probability is 99.96%
Step-by-step explanation:
Given;
number of teachers = 5
number of students = 20
Total number of committee members = 25
Possible outcome of all the members in the 4 committee = 25C₄ ways
= 12650
If the committee must consist at least one student, then the possible outcome;
= Total possible outcome - committee with no student
= 25C₄ ways - 5C₄ ways (all committee members are teachers)
= 12650 - 5
= 12645
The probability that the committee will consist at least one student;
= 12645 / 12650
= 0.9996
= 99.96%
Therefore, if the committee must consist at least one student, the probability is 99.96%
Answer:
6
Step-by-step explanation:
because 9 times 6 is 54 therefore z is 6
