Answer:
The area of the high school field’s base path is (4x^2 -12x + 9) ft^2
The area of the middle school field’s base path is ( x^2 -16x + 64) ft^2
The difference in size between the two is
(3x^2 +4x - 55) ft^2
Step-by-step explanation:
Firstly, we are to calculate the area of the high school field’s base path
Mathematically, the area of a square is L^2
where L is the length of the side of the square. The area of the high school field base path is thus;
(2x-3) * (2x-3) = 2x(2x-3) -3(2x-3) = 4x^2 -6x -6x + 9 = (4x^2 -12x + 9) ft^2
The area of the middle school field’s base path can be calculated in a similar fashion
That would be (x-8) * (x-8) = x(x-8)-8(x-8) = x^2 -8x -8x + 64 =( x^2 -16x + 64) ft^2
The difference in size between this two will be;
(4x^2 -12x + 9) - ( x^2 -16x + 64) = 4x^2-x^2-12x+16x+9-64 = (3x^2 +4x - 55) ft^2
