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Basile [38]
3 years ago
15

Plz help me i can't solve this

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0
The first one is B hope this helps
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Chandra spends 15 minutes doing 4 math problems.She spends the same amount of of time on each problem.How many minutes does she
Serjik [45]

Answer: 3 minutes and 45 seconds

Step-by-step explanation: first, you divide 15 by 4 and that's your answer. Hope this helps!

6 0
2 years ago
NEED HELP ASAP!!!!!!!!!!!!!!
-Dominant- [34]

Answer: B

Step-by-step explanation:

4 0
2 years ago
Can you pls help me with this it's about the immune system
slamgirl [31]

Answer:

A Fever is an Inmune system response.

Step-by-step explanation: This is actually an immune system response. A rise in temperature can kill some microbes. Fever also triggers the body's repair process.

7 0
2 years ago
Help pleaseeeeeeeeeeeeeeeeeeeeeee
bixtya [17]

Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

3 0
2 years ago
Identify which of the twelve basic functions listed below fit the description given. 1 ,y1+e y=x,y=xy=*',y = lxl.y = y=e"y= V,y
skelet666 [1.2K]

remember that local minimuns are points in which the function was decreasing and starts increasing.

you can try two ways of doing it, graphing the functions or using derivatives.

since this are twelve functios the easier way is to graph them.

start by function y=x

in this case this function is continously increasing as x increases, which means that it does not have any local maxima or minima.

now do the same for

y=x^2

this graph has a local minima on th

5 0
10 months ago
Read 2 more answers
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