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Dmitrij [34]
2 years ago
7

I really need help with this answer pls help fast

Mathematics
1 answer:
olganol [36]2 years ago
4 0

Step-by-step explanatio

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An 8-meter length connects the triangular front and back of a house roof. The base of the front
Reptile [31]

Answer:

B=3.6h

Step-by-step explanation:

I had the same question on my hw and I guessed that and got it right so

6 0
2 years ago
Write the slope- intercept form of the equation of the line passing through the point (3,5) and parallel to the line y=3x+6.
seropon [69]

Answer: The gradient of the line passing through is 3, thus the equation of the line becomes y=3x-4.

Step-by-step explanation: The parallel lines gradients that have similar gradients, so now we have the gradient of 3 because its similar to the other gradient. To get the equation of the line we use this equation: y=mx+c, we have to substitute the x and y to get the constant c.

5=3(3)+c

c= -4

y=3x+c

3 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
STARTING TOMORROW, WE SUBMlT REPORTS TO REMOVE KATIEhttps://faq.brainly.com/hc/en-us/articles/206215069-How-can-I-report-a-Moder
Anna35 [415]

Answer:

yayyyyy

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can someone help me ! thx!!
Bond [772]
It should be 100 because it has to add up to 180 and 50+30=80 so the third angle must be 100
5 0
3 years ago
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