<em>They took 101 peaches to market.</em>
<u>Check:</u>
In the 1st hour, they sold (101/2 + 1/2) = 102/2 = 51. They had 50 left.
In the 2nd hour, they sold (50/3 + 1/3)=51/3=17. They had (50-17)=33 left.
In the 3rd hour, they sold (33/4 + 3/4) = 36/4 = 9. They had (33-9) = 24 left.
In the final hour, they sold (24/5 + 1/5) = 25/5 = 5. They had (24-5) = 19 left. yay!
Fiona and Camilla took their 19 remaining peaches and went home. Sharing with
their parents and their brother Rowlf, each person had 3.8 peaches for dinner.
There was a lot of activity in the bathroom overnight.
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The key to solving this one is to work it backwards.
-- They had 19 peaches left at the end of the day.
-- During the final hour, the 1/5 of a peach that they sold left them with 19,
so they had 19-1/5 before they sold the 1/5 of a peach.
The 19-1/5 was 4/5 of what they had at the beginning of the final hour.
So, at the beginning of the final hour, they had (5/4)x(19.2) = 24 .
-- During the 3rd hour, the 3/4 of a peach that they sold left them with 24,
so they had 24-3/4 before they sold the 3/4 of a peach.
The 24-3/4 was 3/4 of what they had at the beginning of that hour.
So, at the beginning of the 3rd hour, they had (4/3)x(24.75) = 33 .
Do the same for the 2nd hour.
Then do the same for the 1st hour.
And you'll work your way back up to 101 peaches.
The function the represent the balance in the account as a function of time t is p(t) = 1000 + 40t
<h3><u>Solution:</u></h3>
Given that,
Carmen deposits $1000 into simple interest account
The rate for the account is 4%
To find: function the represent the balance in the account as a function of time t
Given is simple interest account
The formula for simple interest is given as:
Where, "p" is the principal and "r" is the rate of interest and "t" is the number of years
In simple interest,
total amount after "t" years = principal + simple interest
Here in this question, Carmen deposits $1000
Thus we can frame a function as:
total amount after "t" years = principal + simple interest
Where, p(t) is the amount after "t" years and 
is the principal sum
Thus the function is obtained
Answer:
415.63 minutes
Step-by-step explanation:
Growth can be represented by the equation 
. We can find the rate at which it grows by using t=25 minutes and 
or double the amount at that time. The first step we always take is to divide 
by A.
![[tex]\frac{A_{0}}{A}=e^{rt}\\2=e^{r(25)}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7BA_%7B0%7D%7D%7BA%7D%3De%5E%7Brt%7D%5C%5C2%3De%5E%7Br%2825%29%7D)
To solve for r, we will take the natural log of both sides and use log rules to isolate r.
We know 
so we were able to cancel it out and divide both sides by 25.
We solve with a calculator 
We change 0.0277 into a percent by multiplying by 100 to get 2.77% as the rate.
The equation is 
.
We repeat the step above substituting A=5,000,000, =50, and r=0.02777. Then solve for t.
t=415.63 minutes
The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
One half of the lawn is 10,000 ft². That's the limit that the first man
must be careful not to exceed, lest he blindly mow a couple of blades
more than his partner does, and become the laughing stock of the whole
company when the word gets around. 10,000 ft² ... no mas !
When you think about it ... massage it and roll it around in your
mind's eye, and then soon give up and make yourself a sketch ...
you realize that if he starts along the length of the field, then with
a 2-ft cut, the lengths of the strips he cuts will line up like this:
First lap:
(200 - 0) = 200
(100 - 2) = 98
(200 - 2) = 198
(100 - 4) = 96
Second lap:
(200 - 4) = 196
(100 - 6) = 94
(200 - 6) = 194
(100 - 8) = 92
Third lap:
(200 - 8) = 192
(100 - 10) = 90
(200 - 10) = 190
(100 - 12) = 88
These are the lengths of each strip. They're 2-ft wide, so the area
of each one is (2 x the length).
I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it. So I'll just keep going for another
lap, then add up all the areas and see how close he is:
Fourth lap:
(200 - 12) = 188
(100 - 14) = 86
(200 - 14) = 186
(100 - 16) = 84
So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft². If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.
Hey ! Maybe that's the key to the approximate pattern !
Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice. (Approximately.) So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.
So now we have rectangles measuring
(200 x 100), (196 x 96), (192 x 92), (188 x 88), (184 x 84) ... etc.
and the areas of their rectangular strips are
1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.
==> I see that the areas are decreasing by 32-ft² each lap.
So the next few laps are
1040-ft², 1008-ft², 976-ft², 944-ft², 912-ft² ... etc.
How much area do we have now:
After 9 laps, Area = 9,648-ft²
After 10 laps, Area = 10,560-ft².
And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
the total becomes 10,000-ft².
There must still be an easier way to do it. For now, however, I'll leave it
there, and go with my answer of: During the 10th lap.
32 x 74 = 2368
23 - 72 = -49
2368 + 49 = 2417
2417 = ?
