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natta225 [31]
2 years ago
6

PLEASE ANSWER ASAP expand and simplify the following: a) (√6+√3)(√6-√3) b)(√5-√2)(√2+√5)

Mathematics
2 answers:
denis-greek [22]2 years ago
5 0

Answer:

{ \bf{a).}} \\ { \tt{( \sqrt{6}  +  \sqrt{3} )( \sqrt{6}  -  \sqrt{3}) }} \\ { \tt{ = ( { \sqrt{6} )}^{2}  -  {( \sqrt{3}) }^{2} }} \\ { \tt{ = 6 - 3}} \\ { \tt{ = 3}} \\  \\ { \bf{b).}} \\ { \tt{( \sqrt{5}  -  \sqrt{2})( \sqrt{2}   +  \sqrt{5} )}} \\ { \tt{ = ( { \sqrt{5} }^{2}) -  { (\sqrt{2} }^{2})  }} \\ { \tt{ = 5 - 2}} \\ { \tt{ = 3}}

olchik [2.2K]2 years ago
3 0

Answer:

(6-3)(5-2)=3×3=9

Step-by-step explanation:

x ^{2}  -  {y}^{2}  = (x - y)(x + y)

( \sqrt{6}  -  \sqrt{3} )( \sqrt{6}  +  \sqrt{3} ) = ( { \sqrt{6} }^{2}  -  { \sqrt{3} }^{2} ) = 6 - 3 = 3

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

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Step-by-step explanation:

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Kisachek [45]

Answer:

3 shirts, 6 shorts

Step-by-step explanation:

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Answer:

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