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2 years ago

Find the coordinates of the image of a triangle with vertices A(0, – 3), B(3, 0), and

Mathematics

1 answer:

lora16 [44]2 years ago

8 0

Answer:

A'(-3,0), B'(0,-3) and C'(4,7)

Step-by-step explanation:

We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).

We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.

90° clockwise about the origin

Rule: $(x,y)\rightarrow (y,-x)$

Using the rule

The coordinates of A'

$A(0,-3)\rightarrow A'(-3,0)$

The coordinates of B'

$B(3,0)\rightarrow B'(0,-3)$

The coordinates of C'

$C(-7,4)\rightarrow C'(4,7)$

Hence, the vertices of image of triangle is given by

A'(-3,0), B'(0,-3) and C'(4,7)

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Gloria sold 78 apples, Berta sold 4 less than 9 times as many apples as Gloria. How many apples did Berta Sell?

slega [8]

Answer:

698 apples

Step-by-step explanation: 78*9 equals 702. She sold 4 less than that so you need to subtract 4. 702-4=698 apples Berta sold.

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3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

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3 years ago

Write the equation of the conic section with the given properties:

timurjin [86]

Answer:

$\frac{x^2}{64} + \frac{y^2}{25} =1$

Step-by-step explanation:

An ellipse with vertices (-8, 0) and (8, 0)

Distance between two vertices = 2a

Distance between (-8,0) and (8,0) = 16

2a= 16

so a= 8

Vertex is (h+a,k)

we know a=8, so vertex is (h+8,k)

Now compare (h+8,k) with vertex (8,0) and find out h and k

h+8 =8, h=0

k =0

a minor axis of length 10.

Length of minor axis = 2b

2b = 10

so b = 5

General formula for the equation of horizontal ellipse is

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b} =1$

a= 8 , b=5 , h=0,k=0. equation becomes

$\frac{(x-0)^2}{8^2} + \frac{(y-0)^2}{5} =1$

$\frac{x^2}{64} + \frac{y^2}{25} =1$

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3 years ago

The product of six and a number is multiplied by nine

alex41 [277]

6 + y × 9 (the x is a times sign btw)

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3 years ago

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Please help asap calculate the slope of the line through the points (6,-8) and (3,-4).

sammy [17]

Answer: y = -4/3x + 0. Yes, that point lies on the line

Step-by-step explanation:

Use this equation, Δy/Δx and this one, y = mx + b. Or, change in the y value divided by the change in the x value.

-4 + 8 = 4

3 - 6 = -3

The slope, m, is -4/3. Now solve for b by plugging in the slope.

$-4 = \frac{-4}3 (3) + b$ . B is equal to 0

To see if that point lies on the function, plug it in the equation and see if it is true. Multiply -4 x -3 to get 12, divide by 3 to get 4, then add 0. The equation says that 4 = 4, which is infact true

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3 years ago

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