Answer:
The equation is given below as
Step 1:
We will work on the left-hand side, we will have
By substituting the identity above, we will have
Here, we will make use of the quotient identity
Step 2:
By writings an expression, we will have
Here, we will use the definition of subtraction
Step 3:
We will apply the double number identity given below
By applying this, we will have
Here, we will use the double number identity
Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.