Let x be the number of minutes Peg and Larry used their phones. So their costs can be written as:
Cost of Peg's Phone usage = 25 + 0.25x
Cost of Larry's Phone usage = 35 + 0.20x
We are to find when the Peg's phone will be more than Larry's phone. We can set up the inequality as:
25 + 0.25x > 35 + 0.20x
Re-arranging the inequality
0.25x - 0.20x > 35 - 25
0.05x > 10
x > 10/0.05
x > 200
Thus, Pag's phone will cost more if the number of minutes of phone usage is more than 200
tan2x*cotx - 3 = 0
We know that: tan2x = sin2x/cos2x and cotx = cosx/sinx
==> sin2x/cos2x *cosx/sinx = 3
Now we know that sin2x = 2sinx*cosx
==> 2sinxcosx/cos2x * cosx/sinx = 3
Reduce sinx:
==> 2cos^2 x/ cos2x = 3
Now we know that cos2x = 2cos^2 x-1
==> 2cos^2 x/(2cos^2 x -1) = 3
==> 2cos^2 x = 3(2cos^2 x -1)
==> 2cos^2 x = 6cos^2 x - 3
==> -4cos^2 x= -3
==> 4cos^2 x = 3
==> cos^2 x = 3/4
==> cosx = +-sqrt3/ 2
<span>==> x = pi/6, 5pi/6, 7pi/6, and 11pi/6</span>
This In Expression Form Is:
3r + 4t.
The Reason Why Is Because:
When You Triple r, That Is 3r, And When You Quadruple t, It becomes 4t. And Plus Means to Add. So, This Becomes 3r + 4t
I Hope this Helps!
Answer:
<h2>The answer is 15cm</h2>
Step-by-step explanation:
Let b be the length of the second parallel side
Area of a trapezium is given by
where
h is the height
a and b are the parallel sides
From the question
Area = 230 cm²
height = 20cm
one of parallel side / a = 8 cm
Substitute the values into the above formula and solve for b
That's
Reduce the fraction with 2
That's
Expand the terms
That's
Divide both sides by 10
We have the final answer as
<h3>b = 15cm</h3>
Hope this helps you
To do this you need to know simultaneous equations (which i don’t know if you have learnt it) but this is really hard to explain by words so i hope you can understand by the working out i did
