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salantis [7]
3 years ago
11

Plz help me it says show work to I’m confused

Mathematics
2 answers:
Leni [432]3 years ago
7 0

Answer:

1 = 7x=42 (divide both sides by 7)

7x/7 =42/7

x=6

2.=9y=81 (divide both sides by 9)

9y/9y= 81/9

y=9

3.= –40=8a (divide both sides by 8)

–40/8= 8a/8

a=5

4.=y divided 11=12

y=11 multiplied by 12

y= 132

5.= –15y=135( divide both sides by –15)

–15y/–15=135/–15

y= –9

6.= 17p=51(divide both sides by 17)

17p/17=51/17

p=3

7.= –65= –13w (divide both sides by 13)

–65/–13=–13w/–13

w=5

8.=y/–2=4

(cross multiply)

y/–2=4/1

4 multiplied by –2= –8

therefore:y= –8

Step-by-step explanation:

I HOPE THIS HELPED :)

maks197457 [2]3 years ago
3 0

Answer:

a) 7x=42

Step-by-step explanation

use the co-efficient of the unknown to divide both sides

7x=42

7x/7=42/7

x=6

9y=81

9y/9=81/9

y=9

-40=8a

is the same thing as

-8a=40

-8a/-8=40/-8

a=-5

y+11=12

y=12-11

y=1

-15y=135

-15y/-15=135/-15

y=9

17p=51

17p/17=51/17

p=3

-65=-13w

13w=65

13w/13=65/13

w=5

y/-2= 4

cross multiply y=-8

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<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
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We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

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\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

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\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

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\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

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\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

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<h3>know more :-</h3>

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