I am pretty sure it is 16
-22 is negative which no matter how high the negative number is the positive will always be greater. 25 is greater! :0 - hope I helped
Answer:
The correct answer is A) 3x - 2
Step-by-step explanation:
In order to find this, take the value of JM and subtract the value of LM. This will give you JL.
JM - LM = JL
5x - 8 - (2x - 6) = JL
5x - 8 - 2x + 6 = JL
3x - 2 = JL
Total distance traveled in 20 gallons of gasoline = 580 miles
Total distance traveled in 1 gallon of gasoline =
= 29 miles
Now, we have to calculate the number of miles Maralah can drive in 2,3,4,5,6,7,8,9 ans 10 gallons of gasoline.
Since, number of miles traveled in 1 gallon of gasoline = 29 miles
Number of miles traveled in 2 gallons of gasoline = = 58 miles.
In the similar way, we will make a table which shows the number of miles she can drive her car for 1,2...10 gallons of gasoline.
Refer to the table in attached image.
Answer:
-3/2
(2x-14)/3
(-2,-6)
Step-by-step explanation:
I solved the first one for you already ( -3/2)
To make a line perpindicular to another line they need to intersect at a 90 degree angle. To do this the slope of the lines have to be the negative reciprical (take the fraction, flip it, and apply a negative sign to it)
If you do this to -3/2 you get 2/3
If we follow our y=mx+b equation from before we (so far) have
2/3x+b=y
which means that we just need to solve for b
We also know that it crosses the point (7,0) which means that if we plug in 7 for x and 0 for y we can solve for b
we have
(2/3)*7+b=0
Solve for B
14/3+b=0
b= -14/3
Which means our equation looks like this
(2x-14)/3
our two equations look like this
(-3/2)x-9
(2x-14)/3
We need to find where their coordinates are the same (where they intersect)
We can do this by setting them equal to each other and then solving for x
we have
(-3/2)x-9=(2x-14)/3
solve for x
-4.5x-27=2x-14
-13= 6.5x
x= -2
Now that we know what x equals we can plug this into any of our two beginning equations
(-3/2)*-2-9=y
3-9=y
-6=y
Which means our coordinates are (-2,-6)
if you have any questions let me know