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2 years ago

(7 point)

Mathematics

2 answers:

Vladimir [108]2 years ago

5 0

The number of social media post of Noami has a greater spread when compared to that of Amir.

<h3 /><h3>What is the range and intequartile range of the social media posts?</h3>

Range is the difference between the highest and lowest values of a set of observations

Range = highest value - lowest value

The range of Amir's social media posts = 19 - 15 = 4
The range of Noami's social media posts = 10 - 0 = 10

The inter quartile range is the difference between the third quartile and the first quartile of a data set.

IQR = Q3 - Q1

The IQR of Amir's social media posts: 7

The IQR of Naomi's social media posts = 10

To learn more about range, please check: brainly.com/question/12372689

Yuki888 [10]2 years ago

3 0

Answer:

Naomi"s data set has more spread since her range is 10 and her IQR is 3.

Step-by-step explanation:

Range IQR

12,14,15,15,16,19 16-14=2

0,2,2,4,5,10 5-2=3

19-12=7 10-0=10

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Y=f(x)=(1/3)^x find f(x) when x=2

Sladkaya [172]

Answer:

f(2)=1/9

Step-by-step explanation:

f(x)=(1/3)^x

f(2)=(1/3)^(2)

f(2)=1/9

6 0

3 years ago

Please help me I really need the answer!

Ymorist [56]

(2, 8)

Because you cannot divide by 0, which 2 would do to the bottom.

5 0

3 years ago

Q4.

goblinko [34]

The coding of the statistic is used to make it easier to work with the large sunshine data set

The mean of the sunshine is 3.05 $\overline 6$

The standard deviation is approximately <u>18.184</u>

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Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

$Mean, \ \overline x = \dfrac{\sum x_i}{n}$

The mean of the daily total sunshine is therefore;

$Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6$

$s = \dfrac{x}{10 } - \dfrac{1}{10}$

$E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}$

$E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6$

The mean ≈ 3.05 $\overline 6$

Alternatively

, $The \ mean \ of \ the \ daily \ total \ sunshine, \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6$

The mean of the daily total sunshine, $\overline s$ ≈3.05 $\overline 6$

$Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)$

$Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)$

Therefore;

$Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537$

Therefore;

$s = \sqrt{330.6537} \approx 18.184$

The standard deviation, $s_s$ ≈ <u>18.184</u>

Learn more about coding of statistic data here:

brainly.com/question/14837870

3 0

2 years ago

Consider the following system of equations: y = −2x + 3 y = x − 5 Which description best describes the solution to the system of

Anton [14]

Y= -2x + 3
y = x - 5
y = y
-2x + 3 = x - 5
5 + 3 = 2x + x
8 = 3x
8/3 = x
2.67 = x

4 0

2 years ago

I need help like asap thank youuu

zlopas [31]

CD = √50

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7 0

2 years ago