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2 years ago

Statement: 4x < 0 Which is greater? 1 or x

Mathematics

1 answer:

ch4aika [34]2 years ago

6 0

Answer:

1 is greater than x

Step-by-step explanation:

4x < 0

x<0-4

x< -4

x={ -5,-6,-7,-8,-9,-10,.............}

so {-5,-6,-7,-8,-9,-10,-.............} are lesser than 1

hence 1 >x 0r 1 is greater than x

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Who is faster?

Kay [80]

Kendra is going faster. You could convert Kendra's measurement to feet per second by doing to following:

0.25 mi/1 min x 5280 ft/1 mi x 1 min/60 sec

Which equals:

(0.25)(5280)ft/60 sec

Simplify, and Kendra's speed is 22 feet per second.

mi= mile(s)
min= minute(s)
ft= feet
sec= second(s)

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2 years ago

Where does the line y = -4x + 9 cross the y-axis?

Zanzabum

Answer:

slope is -4 y-axis is 9

Step-by-step explanation:

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3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

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1 year ago

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Semmy [17]

Answer:

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Step-by-step explanation:

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Vikentia [17]

The answer to this question is 29

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2 years ago