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Basile [38]
3 years ago
8

What is the value of the sum? - 3/8+ 5/10 -11/16 -1/16 1/16 1/4 -1/4

Mathematics
1 answer:
mafiozo [28]3 years ago
7 0
First, you must convert the decimals to have the same denominator.

Find the least common multiple of both fractions' denominators:

Multiples of 8: {8,16,24,32,40}
Multiples of 10: {10,20,30,40}

The least common multiple of 8 and 10 is 40.

Multiply the fractions by a number that will make their denominator 40:

- \frac{3}{8} \times  \frac{5}{5} = - \frac{15}{40}
\frac{5}{10} \times \frac{4}{4} = \frac{20}{40}

Now you can add these fractions together:

-\frac{15}{40} + \frac{20}{40} = \frac{5}{40}

Simplify this fraction:

\frac{5}{40} \div \frac{5}{5} = \frac{1}{8}

The answer should be 1/8.

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How much more would $1,000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the int
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Answer: There is a difference of $ 1.0228.

Explanation: Given, initial amount or principal = $ 1000,

Time= 5 years and given compound rate of interest = $3.7%

Now, Since the amount in compound continuously,

A= Pe^{rt} , where, r is the rate of compound interest, P is the principal amount and t is the time.

Here, P=$ 1000, t=5 years and r= $3.7%,

Thus, amount in compound continuously ,  A=1000e^{3.7\times5/100}

⇒A=1000e^{18.5}=1000\times 1.20321844013=1203.21844013

Therefore, interest in this compound continuously rate =1203.21844013-1000=203.21844013

now, Since the amount in compound quarterly,

A=P(1+\frac{r/4}{100} )^{4t}, where, r is the rate of compound interest, P is the principal amount and t is the time.

Thus, amount in compound quarterly, A=1000(1+\frac{3.7/4}{100} )^{4\times5}

⇒A=1000(1+\frac{3.7}{400} )^{20}

⇒A=1000(1+\frac{3.7}{400} )^{20}

⇒A= 1202.19567617

Therefore, interest in this compound quarterly rate=1202.19567617-1000=202.19567617

So, the difference in these interests=203.21844013-202.19567617=1.02276396 ≈1.0228                                                  

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