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Roman55 [17]
3 years ago
14

THERE ARE 120 CHOCOLATES AND SOME BOXES. EACH BOX HOLDS 9 CHOCOLATES. WHAT IS THE LEAST AMOUNT OF BOXES THAT WILL BE NEEDED ?​

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer: 13

Step-by-step explanation:

first divide and then it comes out 13 then check your math so then it puts 120 its correct

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3 years ago
3. Use the given information about the polynomial graph to write out the equation.
scZoUnD [109]

Answer:

f(x)=-\frac{1}{12}(x-3)^2(x+2)^2(x-4)

Step-by-step explanation:

The standard form for a polynomial equation in its factored form is:

f(x)=a(x-p)(x-q)...

Where p and q are the zeros and a is the leading coefficient.

We know that the degree of the polynomial is 5.

We are also given roots at x=3 and x=-2. Hence, our factors are (x-3) and (x+2).

These have a multiplicity of two, so we will square them.

We also know that there is a root at x=4. Hence, the factor is (x-4). This has a multiplicity of 1.

Therefore, our polynomial is now:

f(x)=a(x-3)^2(x+2)^2(x-4)

We know that the y-intercept is 12. Therefore, if we substitute in 0 for x, we should get 12 for y. Here, we are solving for our a. Therefore:

12=a(0-3)^2(0+2)^2(0-4)

Evaluate:

12=a(9)(4)(-4)

Evaluate:

-144a=12

Divide both sides by -144:

a=-1/12

Hence, our entire polynomial is:

f(x)=-\frac{1}{12}(x-3)^2(x+2)^2(x-4)

4 0
3 years ago
Point B has coordinates ​(4,1). The​ x-coordinate of point A is -4. The distance between point A and point B is 10 units. What a
klasskru [66]

Given:

Point B has coordinates ​(4,1).

The​ x-coordinate of point A is -4.

The distance between point A and point B is 10 units.

To find:

The possible coordinates of point​ A.

Solution:

Let the y-coordinate of point A be y. Then the two points are A(-4,y) and B(4,1).

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The distance between point A and point B is 10 units.

\sqrt{(4-(-4))^2+(1-y)^2}=10

Taking square on both sides, we get

(8)^2+(1-y)^2=100

(1-y)^2=100-64

(1-y)^2=36

Taking square root on both sides, we get

(1-y)=\pm \sqrt{36}

-y=\pm 6-1

y=1\mp 6

y=1-6 and y=1+6

y=-5 and y=7

Therefore, the possible coordinates of point​ A are either (-4,-5) or (-4,7).

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6.6=w-1.2 What is w??
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Step-by-step explanation:

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