Just a couple of rules are needed to solve this.
a) When secants cross inside a circle, the measure of the angle where they cross is the average of the measures of the intercepted arcs.
b) When secants meet outside the circle, the measure of the angle where they meet is half the difference of the measures of the intercepted arcs.
c) As a corollary to the first rule, if the secants meet on the circle, the angle where they meet is half that of the intercepted arc (because the other angle in the averge is zero).
Answer:
No
Step-by-step explanation:
If A were reversible, then such y coudnt not exist, because A⁻¹y would be a solution of the equation Ax=y. This means that A in not reversible, thus, there exist a non zero vector w in R³ such that A*w = 0. If x' were a solution of Ax =z, then x'' = x'+w is a different solution of the equation: Ax'' = A(x'+w) = Ax'+Aw = z+0 = z. This means that a vector z such that there exist a unique solution for the equation Ax=z cant exist.
Answer: y = 1/2 or y = -1/2
Step-by-step explanation:
First move the 1 to the side with the 0
-4y^2 = -1 // -1 because when you move a number to the other side of the equation you have to multiply -1
Then divide by -4 on each side
y^2 = 1/4
square root each side
|y| = 1/2 // sq rt y^2 becomes an absolute value because when you square root a square it automatically becomes an absolute value
so the answer would be y = 1/2 or -1/2
to check just put it into the equation as y. Both work.
Answer:
Step-by-step explanation:
We can create equivalent ratios by multiplying or dividing both the numerator and denominator of a given ratio by the same number
You can also write ratios 3 different ways:
____ to ____
____ : ____
___/___