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Marysya12 [62]
3 years ago
7

1-4y^2 = 0 Solve the equation

Mathematics
2 answers:
Anestetic [448]3 years ago
7 0

EXPLANATION:

 1-4y^2=0\\1^2-(2y)^2=0\\(1-2y)(1+2y)=0\\

⇒  1-2y=0   or   1+2y=0\\

⇒ 2y=1  or   2y=-1\\

⇒ y= \frac{1}{2}  or  y=\frac{-1}{2}

P/s:   A^2-B^2=(A-B)(A+B)

Ok done. Thank to me :>

Romashka [77]3 years ago
4 0

Answer: y = 1/2 or y = -1/2

Step-by-step explanation:

First move the 1 to the side with the 0

-4y^2 = -1 // -1 because when you move a number to the other side of the equation  you have to multiply -1

Then divide by -4 on each side

y^2 = 1/4

square root each side

|y| = 1/2 // sq rt y^2 becomes an absolute value because when you square root a square it automatically becomes an absolute value

so the answer would be y = 1/2 or -1/2

to check just put it into the equation as y. Both work.

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