Answer:
-6s-c+1
Step-by-step explanation:
(-3s-4c+1)+(-3s+3c)
We have been given the above expression. To find the sum, we simply collect the like terms and combine them;
(-3s-4c+1)+(-3s+3c) = -3s + -3s -4c + 3c + 1
-3s + -3s -4c + 3c + 1 = -3s - 3s + 3c - 4c + 1
-3s - 3s + 3c - 4c + 1 = -6s - c + 1
Therefore;
(-3s-4c+1)+(-3s+3c) = -6s-c+1
Grouping method works best on this one:
<span>ab+a+4+4b=a<span>(b+1)</span>+4<span>(b+1)</span></span>
<span>=<span>(a+4)</span><span>(b+1<span>)
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Take out the gcf (5).
5(x+3)
The inner binomial cannot be factored.
Final answer: 5(x+3)
