It's A. First of all, one of the only 2 things in math that will NEVER be negative is distances/lengths and times. You have a distance here, so because one of your 2 numbers is negative, you have to take the absolute value of the difference. -8-5 = -11, but the absolute value of that is 11. Put the numbers on a number line and count the units between -8 and +5 and there are 11 units between those 2 numbers.
Answer:
6
Step-by-step explanation:
5+8+6+5+10+7+1=42
42/7=6
Gh is a half of DF because it is a midline
2(3x-4)=9x-59
6x-8=9x-59
3x=51
X=17
Answer:
Step-by-step explanation:
The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.
For the integral from [0, 2], the equation of the line is -3x + 6;
For the integral from [2, 3], the equation of the line is 3x - 6.
We integrate then:
and
sorry for the odd representation; that's as good as it gets here!
Using the First Fundamental Theorem of Calculus, we get:
(6 - 0) + (-4.5 - (-6)) = 6 + 1.5 = 7.5