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3 years ago

8

Solve for the value of x.

1 answer:

Westkost [7]3 years ago

6 0

Answer: I haven’t done this in a bit, but I think this is right. Hope this helps!

Step-by-step explanation:

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A counselor surveys a random sample of 60 out of 900 high school students. 75% of them said they were going to college. She used

Leya [2.2K]

Answer:

yes

Step-by-step explanation:

This problem has some information which does not pertain to the answer. The sample size of 60 is not important to the answer. (Sample size is a concern when it comes to deciding if the survey results are valid!)

75% of the sample says they're going to college, so assuming that the same proportion of students in the entire school is going to college, you need to find 75% of 900.

900 x .75 = 675, the same as the counselor's determination.

4 0

4 years ago

I had $5.00. Mom gave me $10.00 while my Dad gave me $30.00. My aunt and Uncle gave me $100.00. I had another $5.00. How much mo

Lerok [7]

Answer:

$150

Step-by-step explanation:

5 + 10 + 30 + 100 + 5 = 150

5 0

4 years ago

Read 2 more answers

Isolate for x, y = mx + b

zavuch27 [327]

Answer:

x = (y - b)/m

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First subtract b from both sides:

y = mx + b

y (-b) = mx + b (-b)

y - b = mx

Next, divide m from both sides:

(y - b)/m = (mx)/m

x = (y - b)/m

x = (y - b)/m is your answer.

~

3 0

3 years ago

Read 2 more answers

Someone please help!

igomit [66]

Answer:

-11/12 make sure you press the negative

8 0

3 years ago

For p = $3000, r = 3.5%,and t = 5 years, Find the balance in an account When interest is compounded (a) quarterly, (b) monthly,a

MAVERICK [17]

Answer:

a) $3,571.02

b) $3,572.9

c) $3,573.74

Step-by-step explanation:

Data provided in the question:

p = $3000,

r = 3.5%,

t = 5 years

a) quarterly

number of periods in a year, n = 4

Interest rate per period = 3.5% ÷ 4 = 0.875%

Now,

$A = p\times \left( 1 + \frac{r}{n} \right)^{\Large{n \cdot t}}$

A = total amount

n = number of times compounded per year

on substituting the respective values, we get

A = 3000 × $\left( 1 + \frac{ 0.035 }{ 4 } \right)^{\Large{ 4 \cdot 5 }}$

A = 3000 × [/tex]\cdot { 1.00875 } ^ { 20 }[/tex]

A = 3000 × 1.19034

A = $3,571.02

b) monthly

number of periods in a year, n = 12

Now,

A = $p\times \left( 1 + \frac{r}{n} \right)^{\Large{n \cdot t}}$

on substituting the respective values, we get

A = 3000 × $\left( 1 + \frac{ 0.035 }{ 12 } \right)^{\Large{ 12 \cdot 5 }}$

A = 3000 × [/tex]\cdot { 1.002917} ^ { 60 }[/tex]

A = 3000 × 1.190967

A = $3,572.9

c) continuously

A = $pe^{r\times t}$

on substituting the respective values, we get

A = 3,000 × $e^{0.035\times 5}$

or

A = 3,000 × $e^{0.175}$

or

A = 3,000 × 1.1912

or

A = $3,573.74

5 0

3 years ago

Read 2 more answers