6x - 3y = 5. (-2 ,−173) (6 , -3) (1,−113) (9 ,163)

Help me please i don't know what to do

astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

$(x-7)(x+2) = 0$

FOIL:

$x^2 + 2x - 7x - 14 = 0$

Simplify:

$x^2 - 5x - 14 = 0$

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

$(x-3)^2=0$

FOIL:

$x^2 - 3x - 3x +9 = 0$

Simplify:

$x^2 - 6x + 9 = 0$

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

$-x^2-x-3=0$

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

$(x+1)(x-1)=0$

This is a perfect square

FOIL:

$x^2-1=0$

a = 1, b = 0, c = -1

e. x-int at $\sqrt{3} , -\sqrt{3}$

our equation will factor to:

$(x+\sqrt{3} )(x-\sqrt{3)} =0$

This is also a perfect square

FOIL and you will get:

$x^2 - 3 = 0$

a = 1, b = 0, c = -3

4 0

1 year ago

Im dying bro help The vertices of a quadrilateral are (2, 3), (3, 8), (7, 5), and (6, 2). Draw the quadrilateral in the coordina

Solnce55 [7]

Okay to the first number in the ordered pair is the x and the second is the y. So (x,y) when you put a dot on the coordinate plane such as (2,3), you have to go the the horizontal line which is x and go over right 2 spaces(depending on how many numbers is one space) then go up 3. Do that same thing for each of the order pairs. Eventually you will have 4 dots. Connect those dots then you will have the quadrilateral. I hope this helps you!

7 0

2 years ago

Please help I Think I'm wrong!!!!

Allisa [31]

2n+2(n-4)=56
2n+2n-8=56
4n-8=56
4n=64
n=16

1st side is 16
2nd side is 12

8 0

3 years ago

What is the equation, in slope-intercept form, of the line that is perpendicular to the line

wolverine [178]

Answer:

y=3/2x+1

Step-by-step explanation:

y-4= -⅔(x-6)

y-4=-⅔x+4

y=-⅔x+4+4

(equation of line 1) y= -⅔x+8 gradient= -⅔

(line 2)gradient=3/2

note* the gradients of perpendicular lines multiplied result to -1

gradient=y²-y²

x²-x¹

3 =y+2

2. x+2

multiply both sides by 2(x+2)to remove the denominators

3(x+2)=2(y+2)

3x+6=2y+4

3x+6-4=2y

3x+2=2y

divide all sides by 2

3/2x+1=y

y=3/2x+1

8 0

2 years ago

The data in this table represents a linear function.

Leviafan [203]

Is 1/2 an answer? That’s what I keep getting

7 0

2 years ago