I like A as the best one
420 = 100*price - (fixed costs)
220 = 60*price - (fixed costs)
If we subtract one from the other one, we get 200 = 40*price, price = 5
that said, fixed costs are 500 - 420 = 80
Now if we move -220 to the right in Answer A, we'll get:
y = 5x -300 + 220 = 5x - 80
So it looks like A describes the model best
The solution to this problem is 5/2a^2b^5
Answer:
The third option
Step-by-step explanation:
the most reasonable
Well, it is a good and interesting question
Such areas could be calculated in a single shoot and also by dividing the whole shape into other shapes and the total area would be the sum of these areas
I prefer the way of a single shoot ...
The figure represents a trapezoid:
its lower base = 21 units
its upper base = 12 units
the normal height between them = 8 units
NOW
The area of a trapezoid = [(sum of bases' lengths) ÷ 2] * height
= [(12 + 21) ÷ 2] * 8 = 132 sq units
Hope that helps
Answer:
4:1
Step-by-step explanation:
x+20 : y+20 = 5 : 2
(x+20)/(y+20) = 5/2
2(x+20) = 5(y+20)
2x+40 = 5y+100
2x = 5y+60 (1)
x-5 : y-5 = 5:1
(x-5)/(y-5) = 5/1
x-5 = 5(y-5)
x-5 = 5y-25
x = 5y-20 (2)
Solve (1) & (2) simultaneously,
2(5y-20) = 5y+60
10y-40 = 5y+60
5y = 100
y = 20
x = 5y-20
x = 5(20)-20 = 100-20
x = 80
x:y
80:20
4:1
