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In-s [12.5K]
3 years ago
6

Limit b⇒0 (Sin b)/b³

Mathematics
1 answer:
Nitella [24]3 years ago
4 0

Answer:

infinity

Step-by-step explanation:

Given the function

Limit b⇒0 (Sin b)/b³

First substitute the value of b into the function to have

Limit b⇒0 (Sin b)/b³

= sin 0/0³

= 0/0 (Ind)

Apply lhospital rule

Limit b⇒0 (d./db(Sin b))/(d/db(b³))

=>Limit b⇒0 (cos b)/3b²

Substitute the value of b

Cos 0/3(0)²

= 1/0

= infinity

Hence the answer is infinity

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