second compound
Let molar mass of x is = X
Let molar mass of y is = Y
Moles of x in second compound = Mass / molar mass = 7 / X
Moles of y in second compound = Mass / molar mass = 4.5 / Y
For second compound
7 / X : 4.5/ Y = 1:1
Therefore
X / Y = 7/4.5
Y / X = 4.5/ 7
The mass of x in first compound = 14g
moles of x in first compound = 14/X
Mass of y in first compound = 3
moles of y in first compound = 3 / Y
14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1
Thus molar ratio in first compound = moles of x / Moles of y = 3:2
Formula = x3y
- The substance that made up of a particular mixture can be regarded as Solute and solvent
- A mixture can be regarded as material which is made up of more than one different Chemical substance or substances , whereby they are not chemically combined.
- Substance could be any matter such as <em>salt, rice, and or compounds</em>
- A mixture can be regarded as physical combination involving two or more substances whereby each entities identities are retained, then mixed in the form such as ;
- <em>solutions</em>
- <em> suspensions </em>
- <em> colloids</em>.
- A mixture could be in this form <em>(Solute + solvent = solution)</em>
Therefore, the substance that made up of a particular mixture can be regarded as <em>Solute and solvent</em>
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43 inHg = 43 inHg*2.54cm/in = 109.22cmHg * 10 mm/cm = 1092.2 mmHg
14.7 psi = 760 mmHg
1092.2mmHg * 14.7psi / 760 mmHg = 21.13 psi
Answer: option D. 21.13 psi
