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2 years ago

A chemical equation is balanced by changing or adding

1 answer:

6 0

<span>A chemical equation is balanced by changing or adding C. numbers in front of molecules, which are called coefficients.
For example:
O2 + 2 H2 ---> 2 H2O (number 2 is added to both sides in order to balance the equation)</span>

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What is the predominant intermolecular force between ibr molecules in liquid ibr?

jasenka [17]

Answer is: dispersion forces.

The London dispersion force is the weakest intermolecular force.

Dispersion force is also called an induced dipole-induced dipole attraction.

The London dispersion force (intermolecular force) is a temporary attractive force between molecules.

The dipole beetween iodine and bromine is weak.

8 0

3 years ago

Read 2 more answers

Please help I will reward Brainly . Thank you for the help in advance

bekas [8.4K]

Usually you just need to give it rest for 6-12 weeks. depending on how large it is surgery may be needed

5 0

3 years ago

How many moles of SnF₂ will be produced along with 48 grams of H₂? *

KIM [24]

Answer: 24 moles of $SnF_2$ are produced.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

${\text{Moles of} H_2}=\frac{48g}{2g/mol}=24moles$

$Sn+2HF\rightarrow SnF_2+H_2$

According to stoichiometry :

1 mole of $H_2$ is accompanied with = 1 mole of $SnF_2$

Thus 24 moles of $H_2$ is accompanied with = $\frac{1}{1}\times 24=24moles$ of $SnF_2$

Thus 24 moles of $SnF_2$ are produced.

8 0

2 years ago

Sodium hydroxide reacts with sulfuric acid according to the equation:

Lelechka [254]

Answer:

27) Double replacement

28) 2NaOH + H2SO4 --> Na2SO4 + 2H2O

6 0

2 years ago

Given a fixed amount of gas held at constant pressure, calculate the volume it would occupy if a 2.00 L sample were cooled from

aliina [53]

Answer:

1.82 L

Explanation:

We are given the following information;

Initial volume as 2.0 L
Initial temperature as 60.0°C
New volume as 30.0 °C

We are required to determine the new volume;

From Charles's law;

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Where, $V_1 and V_2$ are initial and new volume respectively, while $T_1 and T_2$ are initial and new temperatures respectively;

$T_1= 333 K$

$T_2=303K$

$V_1 =2.0L$

Rearranging the formula;

$V_2=\frac{V_1T_2}{T_1}$

$= \frac{(2.0L)(303K)}{333K} \\=1.820 L$

Therefore, the new volume that would be occupied by the gas is 1.82 L

7 0

2 years ago