The carbon-oxygen single bond in a carboxylic acid
Since the question manages to include moles, pressure, volume, and temperature, then it is evident that in order to find the answer we will have to use the Ideal Gas Equation: PV = nRT (where P = pressure; V = volume; n = number of moles; R = the Universal Constant [0.082 L·atm/mol·K]; and temperature.
First, in order to work out the questions, there is a need to convert the volume to Litres and the temperature to Kelvin based on the equation:
250 mL = 0.250 L
58 °C = 331 K
Also, based on the equation P = nRT ÷ V
⇒ P = (2.48 mol)(0.082 L · atm/mol · K)(331 K) ÷ 0.250 L
⇒ P = (67.31 L · atm) ÷ 0.250 L
⇒ P = 269.25 atm
Thus the pressure exerted by the gas in the container is 269.25 atm.
Answer:
The collision theory is defined as the rate of a reaction is proportional to the rate of reactant collisions.
Explanation:
The reacting species should collide with orientation that allows contract between the atoms that will become bonds together in the product.
The collision occurs with adequate energy to permit mutual penetration of the reacting species. The two physical factors based on the orientation and energy of collision, the following reaction with carbon monoxide with oxygen is considered.
2CO(g) + O2(g) → 2CO2 (g)
After collision between the carbon monoxide and oxygen the reaction is
CO(g) + O2(g) → CO2 (g) + O(g)
Based on the theories of chemical reaction the molecules collide with sufficient amount of energy an activated complex is formed.
Answer: C. mollusca and arthropoda
Explanation:
Remembering that
d = m ÷ v
d = ?
m = 89 g
v = 10 cm³
Therefore:
d = 89 ÷ 10
d = 8,9 g÷cm³
