Answer:
Median highland = 16 mm
Median lowland = 16 mm
Step-by-step explanation:
For the highland area :
The sample size, n = 44
Obtain the median value using :
1/2 * (n + 1)th term
1/2 * (44 +1) th term
1/2 * 45 = 22.5th term.
(22nd + 23rd) term / 2
(16 + 16) / 2 = 16 mm
For the lowland area :
1/2 * (n + 1)th term
1/2 * (44 +1) th term
1/2 * 45 = 22.5th term.
(22nd + 23rd) term / 2
(12 + 12) / 2 = 12 mm
Answer:
*thinking*
Step-by-step explanation:
Yea Ima need you to add a picture of the pairs then I should be able to help. Ill follow so ill see when you update
12^3 = 1728; 14^3 = 2744;
Answer:
0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Step-by-step explanation:
Given the data in the question;
sample size n = 28
slope of the least squares regression line of y on x or sample estimate = 0.0623
standard error = 0.0224
95% confidence interval
level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05
degree of freedom df = n - 2 = 28 - 2 = 26
∴ the equation will be;
⇒ sample estimate ± ( t-test) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
{ from t table; (
) = 2.055529 = 2.056
so we substitute
⇒ 0.0623 ± ( 2.056 )( 0.0224 )
Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
103,727,495 in word form is: one hundred three million, seven hundred twenty-seven thousand, four hundred ninety-five.