Question

Can pls someone help me plsss I need help :(

Answer 1

Answer: $7,5.66,39^{\circ}$

Step-by-step explanation:

Given

$IJ=9\\\angle I=51^{\circ}$

from figure, we can write

$\Rightarrow \sin 51^{\circ}=\dfrac{HJ}{9}\\\\\Rightarrow HJ=9\sin 51^{\circ}=6.99\approx 7$

$\Rightarrow \cos 51^{\circ}=\dfrac{HI}{9}\\\Rightarrow HI=9\cos 51^{\circ}\\\Rightarrow HI=5.66$

In right angle trianle, the sum of the remaining two angles is $90^{\circ}$

$\therefore 51^{\circ}+\angle J=90^{\circ}\\\Rightarrow \angle J=90^{\circ}-51^{\circ}\\\Rightarrow \angle J=39^{\circ}$