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Alex Ar [27]
3 years ago
11

Can pls someone help me plsss I need help :(

Mathematics
1 answer:
liraira [26]3 years ago
4 0

Answer: 7,5.66,39^{\circ}

Step-by-step explanation:

Given

IJ=9\\\angle I=51^{\circ}

from figure, we can write

\Rightarrow \sin 51^{\circ}=\dfrac{HJ}{9}\\\\\Rightarrow HJ=9\sin 51^{\circ}=6.99\approx 7

\Rightarrow \cos 51^{\circ}=\dfrac{HI}{9}\\\Rightarrow HI=9\cos 51^{\circ}\\\Rightarrow HI=5.66

In right angle trianle, the sum of the remaining two angles is 90^{\circ}

\therefore 51^{\circ}+\angle J=90^{\circ}\\\Rightarrow \angle J=90^{\circ}-51^{\circ}\\\Rightarrow \angle J=39^{\circ}

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To find:

The value of x.

Solution:

<em>If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.</em>

$\Rightarrow \frac{DE}{EF} =\frac{LM}{MN}

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