All categories

3 years ago

Can pls someone help me plsss I need help :(

Mathematics

1 answer:

liraira [26]3 years ago

4 0

Answer: $7,5.66,39^{\circ}$

Step-by-step explanation:

Given

$IJ=9\\\angle I=51^{\circ}$

from figure, we can write

$\Rightarrow \sin 51^{\circ}=\dfrac{HJ}{9}\\\\\Rightarrow HJ=9\sin 51^{\circ}=6.99\approx 7$

$\Rightarrow \cos 51^{\circ}=\dfrac{HI}{9}\\\Rightarrow HI=9\cos 51^{\circ}\\\Rightarrow HI=5.66$

In right angle trianle, the sum of the remaining two angles is $90^{\circ}$

$\therefore 51^{\circ}+\angle J=90^{\circ}\\\Rightarrow \angle J=90^{\circ}-51^{\circ}\\\Rightarrow \angle J=39^{\circ}$

You might be interested in

73.085 in standard form

jeka57 [31]

Eres una pinche pendejha huevona

Hija de tu re Phuta bomba madreh, tienes una cara de vaca y puedes venir a mamrmeh la vergha

7 0

3 years ago

There were 516 tickets sold for a basketball game. The activity cardholder tickets cost 1.25 and the non ticket holders ticket w

xxTIMURxx [149]

Answer:

card holder ticket was 807 and non holder is 403.5 (rounded up) is 403.50. Have a nice day.

3 0

3 years ago

A school quiz cmon guys

faltersainse [42]

I believe its 16...
48 divided by 3!
hope this helps!

8 0

3 years ago

Mary invested $42,000 bonus in an account earing 7.2%annual interest that is compounded continuously. How long in years, will it

Blababa [14]

About 14 years because she would earn $3024 yearly and 3024 multiplied by 14 equals 42336

hope this helps! :)

8 0

3 years ago

In a survey of consumers aged 12 and older, respondents were asked how many cell phones were in use by the household. (No two

bogdanovich [222]

Answer:

The probability that his/her household has four or more cell phones in use is 0.122 or 12.2%.

Step-by-step explanation:

The complete question is: In a survey of consumers aged 12 and older, respondents were asked how many cell phones were in use by the household. (No two respondents were from the same household.) Among the respondents, 215 answered "none", 280 said "one", 362 said "two", 149 said "three," and 140 responded with four or more. A survey respondent is selected at random. Find the probability that his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

We are given that among the respondents, 215 answered "none", 280 said "one", 362 said "two", 149 said "three," and 140 responded with four or more.

A survey respondent is selected at random.

As we know that the probability of any event is calculated as;

Probability = $\frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}$

Here, we have to find the probability that his/her household has four or more cell phones in use;

Number of respondent having four or more cell phones in use = 140

Total number of respondents asked = 215 + 280 + 362 + 149 + 140 = 1146

So, the required probability = $\frac{140}{1146}$

= 0.122 or 12.2%

No, it is not unlikely for a household to have four or more cell phones in use because the probability is not less than or equal to 0.05 but in actual it is greater than 0.05.

6 0

3 years ago