Help asap please I'm stuck and I gotta leave soon

A triangle ABC is reflected across the y-axis and then translated 5 units down to triangle A'B'C'. How are the side lengths of t

Oksi-84 [34.3K]

Answer:

d, c, a, b

d= 32, 56

c = 34, 64

a = 85, 92

b = 23, 55

Step-by-step explanation:

3 0

2 years ago

(8.99x10^15) in standard form

Hoochie [10]

8990000000000000 i think

5 0

3 years ago

Two different types of polishing solutions are being evaluated for possible use in a tumble-polish operation for manufacturing i

Nina [5.8K]

Answer:

$z=\frac{0.843-0.653}{\sqrt{0.748(1-0.748)(\frac{1}{300}+\frac{1}{300})}}=5.358$

$p_v =2*P(Z>5.358) = 4.2x10^{-8}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that we have singificantly differences between the two proportions.

Step-by-step explanation:

Data given and notation

$X_{1}=253$ represent the number with no defects in sample 1

$X_{2}=196$ represent the number with no defects in sample 1

$n_{1}=300$ sample 1

$n_{2}=300$ sample 2

$p_{1}=\frac{253}{300}=0.843$ represent the proportion of number with no defects in sample 1

$p_{2}=\frac{196}{300}=0.653$ represent the proportion of number with no defects in sample 2

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference in the the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} - p_2}=0$

Alternative hypothesis: $p_{1} - p_{2} \neq 0$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{253+196}{300+300}=0.748$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.843-0.653}{\sqrt{0.748(1-0.748)(\frac{1}{300}+\frac{1}{300})}}=5.358$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>5.358) = 4.2x10^{-8}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that we have singificantly differences between the two proportions.

5 0

3 years ago

A camera manufacturer spends $2,250 each day for overhead expenses plus $6 per camera for labor and materials. The cameras sell

andriy [413]

2250 + 6x = 16x
2250 = 16x - 6x
2250 = 10x
2250/10 = x
225 = x <=== they must sell 225 cameras to equal daily costs

if they increase production by 50.......x = 225 + 50 = 275
16(275) - 6(275) - 2250 = 4400 - 1650 - 2250 = 4400 - 3900 = 500.
Their daily profit would be $500.

8 0

3 years ago

Read 2 more answers

The sum of the first 100 positive numbers?

ladessa [460]

S ( s + 1)/ 2
so <span>The sum of the first 100 positive numbers

100(100 + 1) / 2
= 50(101)
= 5050</span>

6 0

3 years ago