Hello there!
There are two ways to find the minimum value of this function, but before I show you how, I am going to teach you a little bit about minimum value.
The minimum value on a parabola is the vertex or turning point. This means that the slope of the tangent line is horizontal, having a slope of 0.
The algebraic way to find the minimum or maximum value on a parabola is to use the formula -b/2a. Let's do it...
y=4x^2+4x-35
where a=4, b=4, and c=-35
-b/2a
-4/2(4)
-4/8
-1/2
Now let me show you the other way...
Take the derivative of
y=4x^2+4x-35
y'=8x+4
And set it equal to 0...
8x+4=0
8x=-4
x=-1/2
We got the same answer. Now that we know x=-1/2, plug this into the original equation to find y.
y=4x^2+4x-35
y=4(-1/2)^2+4(-1/2)-35
y=-1-2-35
y=-38
So the minimum point on this parabola is (-1/2,-38)
I really hope th
You formed a right-angled triangle. I drew this out at first, but you can double check it as 579² + 772² = 965², which is the rule for a right-angled triangle. I hope this helps!
In the given triangle, y = 32°.
Step-by-step explanation:
Step 1; In the given triangle, the opposite side has a length of 9cm while the hypotenuse of the triangle measures 17cm. As we have the lengths of the opposite side and the hypotenuse side, we can calculate the sine of the value y.
sin y = 
.
Step 2; Length of the opposite side = 9 cm.
Length of the hypotenuse side = 17 cm.
sin y = = 
= 0.5294.
We can multiply inverse sine on both sides to solve y.
y = 
(0.5294) = 31.9657°.
Rounding this off to the nearest tenth we get, y = 32.0°.
I believe it would be y= -1
Decimals are always written with digits, what is your question?
