Your range on a graph always the values that y could possibly be. These often include infinity since lines trend in one direction or the other.
Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²
Answer:
Step-by-step explanation:
- Choose 2 points on the graph. (-2,8) (3,-7)
- Apply slope formula.
I hope I choose the right cordinates...
0.2 is your answer is the answer you need to get. You need to divide 50 divided by 10 and your answer will be 0.2.
Answer:
x=-12
Step-by-step explanation:
Start by getting all of the x values on one side and other to the other.
1/3x-3/4x=1+4
Now simplify. Because 1/3 and 3/4 do not have the same denominator, find the least common factor between 3 and 4 (which is 12) and make the fractions have denominators of 12.
4/12x-9/12x=5
-5/12x=5
x=5*(12/-5)=60/-5=-12
x=-12
