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artcher [175]
3 years ago
8

Help me with this please​

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer: B

Step-by-step explanation:

Well if it's a greater than statement you can rule out C and D because those are less than symbols ( > = Less,  < = Greater) It can't be A because thats his starting amount. The x means how many months it will take for him to get more than 70 stamps

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What is 15 hours and 60 minutes in simplest form
Lilit [14]
Good Afternoon,

Okay so we have 15 hours already, now we need to add 60 minutes, which is exactly an hour. 

So, 15 Hours + 1 Hour = 16 Hours. 

16 Hours is your answer, I hope I helped and good luck studying!

Thank you, 
Darian D. 
8 0
3 years ago
there is a walking trail at the park. four laps around the trail is a distance of 1 mile. how many laps does it take to walk 3/4
dybincka [34]
1 ÷ 4 1/4 so one lap is a quarter of a mile meaning 3 laps is 3/4 of a mile
4 0
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У = х — 22<br> Perpendicular?
Romashka-Z-Leto [24]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
How do you get an equation to solve for all 3 sides of a triangle?
slavikrds [6]

In your solving toolbox (along with your pen, paper and calculator) you have these 3 equations:

1. The angles always add to 180°:

A + B + C = 180°

When you know two angles you can find the third.

 

2. Law of Sines (the Sine Rule):

Law of Sines

When there is an angle opposite a side, this equation comes to the rescue.

Note: angle A is opposite side a, B is opposite b, and C is opposite c.

 

3. Law of Cosines (the Cosine Rule):

Law of Cosines

This is the hardest to use (and remember) but it is sometimes needed  

to get you out of difficult situations.

It is an enhanced version of the Pythagoras Theorem that works  

on any triangle.

With those three equations you can solve any triangle (if it can be solved at all).

Six Different Types (More Detail)

There are SIX different types of puzzles you may need to solve. Get familiar with them:

1. AAA:

This means we are given all three angles of a triangle, but no sides.

AAA Triangle

AAA triangles are impossible to solve further since there are is nothing to show us size ... we know the shape but not how big it is.

We need to know at least one side to go further. See Solving "AAA" Triangles .

 

2. AAS

This mean we are given two angles of a triangle and one side, which is not the side adjacent to the two given angles.

AAS Triangle

Such a triangle can be solved by using Angles of a Triangle to find the other angle, and The Law of Sines to find each of the other two sides. See Solving "AAS" Triangles.

 

3. ASA

This means we are given two angles of a triangle and one side, which is the side adjacent to the two given angles.

ASA Triangle

In this case we find the third angle by using Angles of a Triangle, then use The Law of Sines to find each of the other two sides. See Solving "ASA" Triangles .

 

4. SAS

This means we are given two sides and the included angle.

SAS Triangle

For this type of triangle, we must use The Law of Cosines first to calculate the third side of the triangle; then we can use The Law of Sines to find one of the other two angles, and finally use Angles of a Triangle to find the last angle. See Solving "SAS" Triangles .

 

5. SSA

This means we are given two sides and one angle that is not the included angle.

SSA Triangle

In this case, use The Law of Sines first to find either one of the other two angles, then use Angles of a Triangle to find the third angle, then The Law of Sines again to find the final side. See Solving "SSA" Triangles .

 

6. SSS

This means we are given all three sides of a triangle, but no angles.

SSS Triangle

In this case, we have no choice. We must use The Law of Cosines first to find any one of the three angles, then we can use The Law of Sines (or use The Law of Cosines again) to find a second angle, and finally Angles of a Triangle to find the third angle.

7 0
3 years ago
Read 2 more answers
PROBLEM #1
lesantik [10]

Answer:

  • 500 - 25w ≥ 200

Explanation:

Translate every verbal statement into an algebraic statement,

<u>1. Keith has $500 in a savings account at the beginning of the summer.</u>

  • Initial amount: 500

<u>2.  He wants to have at least $200 in the account by the end of summer. </u>

<u />

  • Final amount ≥ 200

<u>3. He withdraws $25 a week for his cell phone bill.</u>

<u />

  • Call w the number of weeks
  • Withdrawls = 25w

<u>4. Write an inequality that represents Keith's situation.</u>

  • Create your model: Final amount = Initial amount - withdrawals ≥ 500

  • 500 - 25w ≥ 200

With that inequality you can calculate how many week will pass before his account has less than the amount he wants to have in the account by the end of summer:

  • 500 - 200 ≥ 25w
  • 300 ≥ 25w
  • 300/25 ≥ w
  • 12 ≥ w
  • w ≤ 12

That represents that he can afford spending $ 25 a week during 12 weeks to have at least $ 200 in the account.

8 0
3 years ago
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