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Kamila [148]
3 years ago
11

Which of the following code displays the area of a circle if the radius is positive? Question 4 options: if (radius <= 0) Sys

tem.out.println(radius * radius * 3.14159); if (radius != 0) System.out.println(radius * radius * 3.14159); if (radius >= 0) System.out.println(radius * radius * 3.14159); if (radius > 0) System.out.println(radius * radius * 3.14159);
Computers and Technology
1 answer:
Marina CMI [18]3 years ago
3 0

Answer:

(d) if (radius > 0) System.out.println(radius * radius * 3.14159);

Explanation:

Given

Code segment (a) to (d)

Required

Which is correct

Code segment (a): radius <=0

This means that radius is 0 or less, i.e. 0 or negative

Code segment (b): radius !=0

This means that radius is not equal to 0 i.e. it could be positive or negative but definitely not 0

Code segment (c): radius >=0

This means that radius is 0 or greater, i.e. 0 or positive

Code segment (d): radius >0

This means that radius is  greater than 0 i.e. positive

<em>Hence, (d) is correct</em>

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You are an interior decorator, confronted with a dark living room. To lighten the room up, you have n candles and want to build
user100 [1]

Answer:

a)

Algorithm to find a solution of min. cost

Function:cost(Graph G,Graph G1);

GC --> empty graph

for i in edges E:

if E(i,j) in G:

c(i,j)=c(i,j)

else if E(i,j) in G1:

c(i,j)=-c(i,j)

Function:Mincost(Graph G):

GC=Cost(G,G1)

while(negativecycle(GC)):

Update residal graph(G1)

GC=Cost(G,G1)

mincost=sum of Cij*F(i,j)

return mincost;

Explanation:

a)

1) Start the program

2) Read the no. of edges and vertices and also read the cost of the two nodes.

3) Find the min cost by travelling to the destination i.e.. finding all possible min. cost values.

4) Compare the all possible min.cost values

5) And display the least min. cost

6) Stop the program

b)

<u>Correctness of algorithm</u>

1)Here in these algorithm we are calculating all the possible cases.

2)These algorithm also supports the negative cost.

3)These algorithm occupies more space.

4)Takes less time

5)so,these algorithm provides the cost efficient solution very effectively.

c)

<u>Run Time Analysis</u>

1) While reading the values during the run time the program execution will stop until user provides the values.

2) Based on the User input Output vary.

3) Time consumption and space consumption is depends on the no. of inputs the user is given.

6 0
4 years ago
Given the statement: int list[25]; The index can go from 0 to 25 inclusive withoutgoing beyond the end of the array.true or fals
k0ka [10]

Answer:

False.

Explanation:

When we create an array of size n, then it's index will starts from 0 to n-1. Array index starts with 0 because the first element of the array holds the memory location that refers to 0 element away.Similarly 2nd element of array is 1 distance away from that location. That is why index starts with 0 and goes to n-1 if the size  is n.

In the question question, int list[25] is given. So the index will be from 0

to 25-1 only.If index will goes to 25 then it will go beyond the array.

3 0
3 years ago
MyProgramming Lab
Akimi4 [234]

Answer:

Explanation:

The following code is written in Python. It creates a method for each one of the questions asked and then tests all three with the same test case which can be seen in the picture attached below.

def alternating_list(lst1, lst2):

   lst3 = []

   for x in range(len(lst1)):

       lst3.append(lst1[x])

       try:

           lst3.append(lst2[x])

       except:

           pass

   if len(lst2) > len(lst1):

       lst3.extend(lst2[len(lst1):])

   return lst3

def reverse_alternating(lst1, lst2):

   lst3 = []

   if len(lst1) == len(lst2):

       for x in range(len(lst1) - 1, -1, -1):

           lst3.append(lst1[x])

           lst3.append(lst2[x])

   return lst3

def alternating_list_no_extra(lst1, lst2):

   lst3 = []

   max = 0

   if len(lst1) > len(lst2):

       max = len(lst2)

   else:

       max = len(lst1)

   for x in range(max):

       lst3.append(lst1[x])

       try:

           lst3.append(lst2[x])

       except:

           pass

   return lst3

4 0
3 years ago
In a blockchain, each block has a unique hash value which is dependent on the hash value of the previous block in the chain. Wha
pantera1 [17]

Answer: hello your question lacks the required option, below are the missing options

A. The transaction data in the tampered block is deleted, and a copy is created with the same hash value.

B. The hash values of transaction data of subsequent blocks are validated, and the chain is broken.

C. The hash value for the entire block is nullified, creating a domino effect on all subsequent blocks.

D. The hash values of subsequent blocks are updated as soon as they are tampered with, and the chain continues.

answer : The hash values of subsequent blocks are updated as soon as they are tampered with, and the chain continues ( D )

Explanation:

What happens if a transaction data is changed in an earlier existing block in a Blockchain is that the Hash values of subsequent blocks will be updated as soon as they are tampered with and the chain will continue.

Blockchain is a specially design system for recording information, hence any change in data inputted in an earlier existing blocks that changes will automatically be updated as well in all preceding blocks.

4 0
3 years ago
How do I change my keyboard's debounce time?
Zanzabum

in the control board type:

HKEY_CURRENT_USER\Control Panel\Accessibility\Keyboard Response\BounceTime

3 0
3 years ago
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