Question

Which of the following code displays the area of a circle if the radius is positive? Question 4 options: if (radius <= 0) System.out.println(radius * radius * 3.14159); if (radius != 0) System.out.println(radius * radius * 3.14159); if (radius >= 0) System.out.println(radius * radius * 3.14159); if (radius > 0) System.out.println(radius * radius * 3.14159);

Answer 1

Answer:

(d) if (radius > 0) System.out.println(radius * radius * 3.14159);

Explanation:

Given

Code segment (a) to (d)

Required

Which is correct

Code segment (a): radius <=0

This means that radius is 0 or less, i.e. 0 or negative

Code segment (b): radius !=0

This means that radius is not equal to 0 i.e. it could be positive or negative but definitely not 0

Code segment (c): radius >=0

This means that radius is 0 or greater, i.e. 0 or positive

Code segment (d): radius >0

This means that radius is  greater than 0 i.e. positive

Hence, (d) is correct