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nydimaria [60]
3 years ago
9

GMI = $4,666.67 Total Monthly Deductions $1,131.00 What is the Net Monthly Income (GMI - Total Monthly Deductions) =

Computers and Technology
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

Net Monthly Income = $3,535.67

Explanation:

Given:

GMI = $4,666.67

Total Monthly Deductions = $1,131

Find:

Net Monthly Income

Computation:

Net Monthly Income = GMI - Total Monthly Deductions

Net Monthly Income = $4,666.67 - $1,131

Net Monthly Income = $3,535.67

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Answer:

<h2>Rom</h2>

Explanation:

ROM is memory containing hardwired instructions that the computer uses when it boots up, before the system software loads

4 0
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To create a datetime object for the current date and time, you can use theGroup of answer choicestoday() method of the date clas
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2 years ago
What type of hacker is primarily motivated by an ideology, epitomizing "the ends justify the means" mentality?.
Hunter-Best [27]

The type of hacker that is primarily moved by an ideology, epitomizing "the ends justify the means" mentality is Hacktivism.

<h3>What type of hackers are motivated by social or political issues?</h3>

Hacktivism is known to be an act of the wrong use a computer system or network for a socially or politically motivated  aim or reason.

The type of hacker that is primarily moved by an ideology, epitomizing "the ends justify the means" mentality is Hacktivism and they are called hacktivist.

Learn more about Hacktivism from

brainly.com/question/5483494

#SPJ1

5 0
2 years ago
A user has a network device that streams media to the LAN. The device is visible on the network. All PCs on the LAN can ping the
trasher [3.6K]

Answer: A. Multicast

Explanation:

Here we are given a situation where it is necessary for the device to stream media to all the PCs connected across the LAN. But as the they are unable to stream the media then it is a problem in the multicast TCP/Ip technology.

Multicasting enables to transfer information or messages from one to many or many to many. Here as a single device is responsible for streaming the content to other PCs across the LAN, therefore it is necessary that multicast has been properly implemented.

Option B is incorrect as it is not a scenario of broadcast as in broadcasting all the receivers must get the streaming however here if a PC does not want to receive the media stream it cannot receive for which multicasting is required.

Option C is incorrect as here we are not talking of one to one communication.

Option D is incorrect as here we cannot have more than one route to send the media content except the LAN.

5 0
3 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
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