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nydimaria [60]
3 years ago
9

GMI = $4,666.67 Total Monthly Deductions $1,131.00 What is the Net Monthly Income (GMI - Total Monthly Deductions) =

Computers and Technology
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

Net Monthly Income = $3,535.67

Explanation:

Given:

GMI = $4,666.67

Total Monthly Deductions = $1,131

Find:

Net Monthly Income

Computation:

Net Monthly Income = GMI - Total Monthly Deductions

Net Monthly Income = $4,666.67 - $1,131

Net Monthly Income = $3,535.67

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Is it possible for a PowerPoint user to add notes to slides and see the added comments
Arturiano [62]

Answer:

I am not for sure on this, but yes I think it is possible for the PowerPoint user to add notes to slides and see the added comments. If it isn't possible I know for a fact on Google slides it is possible.

:

hope this helps! :)

7 0
3 years ago
before donating a computer you should use a program to wipe the hardest to remove all of his data true or false
Katarina [22]
True or they could get into your stuff. 
6 0
4 years ago
Write a method named circleArea that accepts the radius of a circle as a parameter (as a real number) and returns the area of a
lions [1.4K]

Answer:

  public static double circleArea(double radius){

       double area = 3.142*Math.pow(radius,2);

       return area;

   }

Explanation:

Find the complete program in java that prompts the user to enter a value for radius, stores it in a variable, calls the method circleArea() and passes the value for the radius, then displays the area.

import java.util.Scanner;

public class CocaColaVendingTest {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Please enter the value for radius");

       double r = in.nextDouble();

       //Calling the method circleArea()

       double calcArea = circleArea(r);

       System.out.println("The Area is: "+calcArea);

   }

   public static double circleArea(double radius){

       double area = 3.142*Math.pow(radius,2);

       return area;

   }

}

6 0
3 years ago
(BRAINLIEST QUESTION!!!)
docker41 [41]

Answer:

Possible if hackers are not so intelligent.

Explanation:

Actually, hackers are intelligent

where they will change location code in different places every second. So end-user who is trying to trace it he or she has to use their intelligence to find the exact location of hackers.

Normally hackers will generate different location places and by using decipher it is possible to find the location codes.

Since hackers used encrypted message we need to decrypts the message and find it out and understand the decrypt and encrypt technology used by hackers.

It is possible to by using decipher to get uncovered locations

4 0
3 years ago
Write a recursive function that takes a non-negative integer as an argument and displays the same number in reverse order (i.e.
avanturin [10]

Answer:

Following are the program in C++ language

#include<iostream> // header file

using namespace std; // namespace std

int reverse(int n1); // function prototype

int main()  // main function()

{

   int num; // Variable declaration

   cout << "Enter the number" << endl;

   cin >> num; // Read the number bu the user

  cout<<"After Reverse the digit:\n";

   int res= reverse(num); // calling function reverse

   

   cout<<res; // display  

}

int reverse(int n1) // function definition of reverse

{

   if (n1<10)  // checking the base condition

       {

           return n1;

       }

   else

       {

           cout << n1 % 10; // Printed the last digit

          return reverse(n1/10); // calling itsself

}

}

Output:

Enter the number:

76538

After Reverse the digit:

83567

Explanation:

Following are the description of the program

  • In the main function read the number by user in the "num" variable of int type.
  • Calling the reverse and pass that "num" variable into it.
  • After calling the control moves to the body of the reverse function.In this function we check the two condition

        1  base condition

   if (n1<10)  // checking the base condition

       {

           return n1;

     }

      2  General condition

  else

       {

           cout << n1 % 10; // Printed the last digit

          return reverse(n1/10); // calling itsself

       }

  • Finally return the reverse number and display them into the main function.
5 0
4 years ago
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