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11Alexandr11 [23.1K]
3 years ago
8

A total investment of $10,700 is made into two savings accounts. One account yields 5% simple interest and the other 6% simple i

nterest. He earns a total of $624.00 interest for the year. How much was invested in the 5% account? $
Mathematics
2 answers:
AlladinOne [14]3 years ago
5 0

Answer:

He earn $535.00 in the 5% account

Step-by-step explanation:

I =  \frac{prt}{100}

I = interest amount

p = $10 700

r = 5%

t = 1 year

I = (10700×5×1)/100

= $535.00

(Correct me if i am wrong)

dangina [55]3 years ago
4 0
He gots a total of $535
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Answer:

P(A) = \frac{30}{100}

P(B) = \frac{77}{100}

P(A\ n\ B) = \frac{22}{100}

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Step-by-step explanation:

Given

See attachment for proper format of table

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

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So, we have:

n(A) = Yes + No

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P(A) is then calculated as:

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P(A) = \frac{30}{100}

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

(1) = 22    (2) = 25 and (3) = 30

So, we have:

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

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And it is represented with; n(A n B)

So, we have:

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

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