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Nostrana [21]
3 years ago
8

Find the​ slope, if it​ exists, of the line containing the pair of points (4,−4) and (−2,−4).

Mathematics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

-6 is the answer of your question

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What’s the equation of a slope of 5/7 and a y-intercept of -3
Drupady [299]

Answer:

Step-by-step explanation:

in y = mx + b form, the slope is in the m position and the y intercept is in the b position.

y = mx + b

slope(m) = 5/7

y int (b) = -3

y = 5/7x - 3 <===

8 0
3 years ago
If (8^9)p = 8^16 what's the value of p?
monitta

Answer:

p  = {8}^{7}

Step-by-step explanation:

(8^9)p = 8^{16 } \\  \\ p =  \frac{8^{16 } }{8^{9 } }  \\  \\  p =  {8}^{16 - 9}  \\  \\  \huge \red{ \boxed{p  = {8}^{7} }}

8 0
2 years ago
You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0
3 years ago
No links pls no links
vodka [1.7K]

Answer:

ok byyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyee6648479786100101010101001010101010010010101001010100101010101010010101001010101110100010100101101001010101001010101000010101010011001010101010010101001

Step-by-step explanation:1001010101001010101001010101010010101010101001010101010101010100101010101010101010101010101010000000000000000111111111110000000001010101001010101010

7 0
2 years ago
A ribbon is cut into n parts. The length of each part increases such that they form a geometric progression. SPM Given the lengt
emmainna [20.7K]

Answer:

Step-by-step explanation:

Let\ say\ r \ the \common\ ratio:\\a)a_4=r^2*a_2=9*a_2\Longrightarrow\ r=3\ (not\ -3\ since\ parts\ are\ positive)\\\\b)\\\displaystyle \sum_{i=1}^{n} a_i =a_1+a_2+a_3+...+a_n\\\\=a_1+a_1*r+a_1*r^2+a_1*r^3+...+a_1*r^{n-1}\\\\=a_1*(1+r+r^2+...+r^{n-1})\\\\=a_1*\dfrac{r^n-1}{r-1} \\\\147620=5*\frac{(3^n-1)}{3-1} \\\\3^n-1=\frac{2*147620}{5} \\\\3^n=59049 \\\\n*ln(3)=ln(59049)\\\\n=\dfrac{ln(59049)}{ln(3)} \\\\n=10\\\\a_n=5*3^{10-1}=5*19683=98415(cm)

5 0
2 years ago
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