12-3=9 they switch up and it still equals the same thing
Answer:
Lowest is 100
Highest is 125
Step-by-step explanation:
We use the 5 number summary to be the foundation of a graphical representation referred to as the box plot. One box would move from one quartile which is the lowest quartile Q1 to the another quartile Q3 which is the upper quartile.
Now if a box plot is to be made given the the information in this question, the box is going to go from Quartile 1 to Quartile 3.
Then the Lowest value would be 100 and the highest 125
(86.8 - 3n)/4
You can get this by combining the two. Make sure to give common denominators.
Step-by-step explanation:
#1 equals 1 1/4
The common denominator for 1/6, 2/3, and 5/12 would be 12. So I made the denominators 12 which means 1/6 would turn into 2/12, 2/3 turns into 8/12, and 5/12 stays the same. When I add them all up I get 15/12. I can turn that into a mixed number which would be 1 3/12. I can simplify that down to <em><u>1 1/4.</u></em>
#2 equals 3/4
The first thing you have to do is turn 2 2/3 and 1 3/4 into improper fractions. Which would turn 2 2/3 into 24/3 and 1 3/4 into 21/12. The next thing is you have to find a common denominator which would be 12. Next you have to turn the denominators into a 12 and change the numerator. Which makes the fractions: 24/12, 6/12, and 21/12. When you add 24/12 and 6/12 together you get 30/12 minus 21/12 you get 9/12. You can then simplify that to <em><u>3/4. </u></em>
#3 equals -1 17/36
The first thing you do is turn 3 5/18 into an improper fraction which would be 59/18. then you find a common denominator which would be 36 and make the denominators of those numbers into 36 which would be 11/36, 54/36, and 118/36. When you add up 11/36 and 54/36 you get 65. but when you - 65 by 118 you get -53 / 36. you can lend turn that into <u>-</u><em><u>1 17/36. </u></em>
I'm not sure about number 4 and I don't want to give you the wrong answer. Hopefully what I did show you helped!
Answer:
(1,-1)
(7,12)
(5,-3)
Step-by-step explanation:
we know that
If a ordered pair is a solution of the inequality, then the ordered pair must satisfy the inequality
we have
Verify each case
case 1) we have
(1,-1)
substitute the value of x and the value of y in the inequality and then compare the results
----> is true
therefore
The ordered pair is a solution of the inequality
case 2) we have
(7,12)
substitute the value of x and the value of y in the inequality and then compare the results
----> is true
therefore
The ordered pair is a solution of the inequality
case 3) we have
(-6,-3)
substitute the value of x and the value of y in the inequality and then compare the results
----> is not true
therefore
The ordered pair is not a solution of the inequality
case 4) we have
(0,-2)
substitute the value of x and the value of y in the inequality and then compare the results
----> is not true
therefore
The ordered pair is not a solution of the inequality
case 5) we have
(5,-3)
substitute the value of x and the value of y in the inequality and then compare the results
----> is true
therefore
The ordered pair is a solution of the inequality
